Expand the following \( 1.2 .1 \quad(a-2)\left(a^{2}\right. \) \( 1.2 .2-(2 x-5)^{2} \) 1.2 .3 \( \quad\left(\frac{a}{2}+1\right) \quad \) ?
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Let's tackle these one by one! For the first expression \((a-2)a^2\), we distribute \(a^2\) to both terms in the parentheses, giving us \(a^3 - 2a^2\). Next, for the expression \(-(2x-5)^{2}\), we need to expand it. Using the formula \((b-c)^2 = b^2 - 2bc + c^2\), we have: \[ -(2x-5)^{2} = -((2x)^2 - 2 \cdot (2x) \cdot 5 + 5^2) = -(4x^2 - 20x + 25) = -4x^2 + 20x - 25. \] For \(\left(\frac{a}{2}+1\right)\), we'll distribute the terms by factoring out \(2\) to make it easier: \[ \frac{1}{2}a + 1. \] In summary, we have: 1. \(a^3 - 2a^2\) 2. \(-4x^2 + 20x - 25\) 3. \(\frac{1}{2}a + 1\)