\( \frac{8}{8}-\frac{1}{8} \) 2. \( 2 \frac{1}{4} x+\frac{1}{2} x=44 \)
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First, let's simplify the expression \( \frac{8}{8}-\frac{1}{8} \). Here, \( \frac{8}{8} = 1 \), so you have \( 1 - \frac{1}{8} \), which equals \( \frac{8}{8} - \frac{1}{8} = \frac{7}{8} \). Now to solve the equation \( 2 \frac{1}{4} x + \frac{1}{2} x = 44 \). First convert \( 2 \frac{1}{4} \) to an improper fraction: \( 2 \frac{1}{4} = \frac{9}{4} \). Therefore, your equation becomes \( \frac{9}{4}x + \frac{1}{2}x = 44 \). To combine the fractions, convert \( \frac{1}{2} \) to fourths, giving you \( \frac{2}{4}x \). This results in \( \left(\frac{9}{4} + \frac{2}{4}\right)x = 44 \), or \( \frac{11}{4}x = 44 \). Multiply both sides by \( \frac{4}{11} \) to isolate \( x \): \( x = \frac{44 \times 4}{11} = 16 \). So, \( x = 16 \).