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Small Business Owners Seventy-six percent of small business owners do not have a college degree. If a random sample of 60 small business owners is selected, find the probability that exactly 47 will not have a college degree. Round the final answer to at least 4 decimal places and intermediate \( z \)-value calculations to 2 decimal places. \( P(X=47)=0.1133 \)

Ask by Bradley Mcfarlane. in the United States
Mar 11,2025

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Answer

The probability that exactly 47 out of 60 small business owners do not have a college degree is approximately 0.1133.

Solution

To find the probability that exactly 47 small business owners out of 60 do not have a college degree, we can use the binomial distribution formula. Given: - \( n = 60 \) (total number of small business owners) - \( p = 0.76 \) (probability of a small business owner not having a college degree) - \( X = 47 \) (number of small business owners not having a college degree) The binomial distribution formula is: \[ P(X=k) = \binom{n}{k} p^k (1-p)^{n-k} \] Substitute the given values into the formula: \[ P(X=47) = \binom{60}{47} (0.76)^{47} (1-0.76)^{60-47} \] Now, we can calculate the probability using the binomial distribution formula. Calculate the value by following steps: - step0: Calculate: \( { }_{60}C_{47}\times 0.76^{47}\left(1-0.76\right)^{60-47}\) - step1: Subtract the numbers: \( { }_{60}C_{47}\times 0.76^{47}\times 0.24^{60-47}\) - step2: Subtract the numbers: \( { }_{60}C_{47}\times 0.76^{47}\times 0.24^{13}\) - step3: Expand the expression: \(\frac{60!}{47!\times \left(60-47\right)!}\times 0.76^{47}\times 0.24^{13}\) - step4: Subtract the numbers: \(\frac{60!}{47!\times 13!}\times 0.76^{47}\times 0.24^{13}\) - step5: Multiply the terms: \(\frac{60!}{129729600\times 48!}\times 0.76^{47}\times 0.24^{13}\) - step6: Divide the terms: \(5166863427600\times 0.76^{47}\times 0.24^{13}\) - step7: Convert the expressions: \(5166863427600\left(\frac{19}{25}\right)^{47}\times 0.24^{13}\) - step8: Convert the expressions: \(5166863427600\left(\frac{19}{25}\right)^{47}\left(\frac{6}{25}\right)^{13}\) - step9: Simplify: \(5166863427600\times \frac{19^{47}}{25^{47}}\times \left(\frac{6}{25}\right)^{13}\) - step10: Multiply the terms: \(\frac{206674537104\times 19^{47}}{25^{46}}\times \left(\frac{6}{25}\right)^{13}\) - step11: Evaluate the power: \(\frac{206674537104\times 19^{47}}{25^{46}}\times \frac{6^{13}}{25^{13}}\) - step12: Multiply the fractions: \(\frac{206674537104\times 19^{47}\times 6^{13}}{25^{46}\times 25^{13}}\) - step13: Multiply: \(\frac{206674537104\times 19^{47}\times 6^{13}}{25^{59}}\) The probability that exactly 47 small business owners out of 60 do not have a college degree is approximately 0.1133.

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The Deep Dive

Did you know that small businesses are vital to the economy? They create about 70% of all new jobs in the United States! This shows that many successful business owners rely on experience rather than formal education, showcasing the importance of skill, innovation, and determination in the entrepreneurial journey. If you’re calculating probabilities like this, it's important to consider the normal approximation to the binomial distribution for larger samples. In your case, since \( p = 0.76 \) and \( n = 60 \), you can use the mean \( \mu = np \) and standard deviation \( \sigma = \sqrt{np(1-p)} \) to find the probabilities more easily. Remember to check that \( np \) and \( n(1-p) \) are both greater than 5 to validate this method!

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