6. Fill in the blanks. $$ \begin{array}{l} ext { a) }(-1) imes \quad ext { b) }(-1) imes(-25)= \ ext { 7. Use the sign },

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6. Fill in the blanks. $$ \begin{array}{l}	ext { a) }(-1) 	imes \quad 	ext { b) }(-1) 	imes(-25)= \ 	ext { 7. Use the sign }>,<	ext { or }=	ext { in the box to make the statement true. } \ \begin{array}{ll}	ext { a) } 2.3-(-35)-18 \ 	ext { b) } 39+(-24)-15 \ 	ext { b } \ 	ext { 8. Rita goes } 20 \mathrm{~km} 	ext { towards east from a point } \mathrm{A} 	ext { to the point } \mathrm{B} 	ext {. From } \mathrm{B} 	ext {, she moves } 30 \mathrm{~km} \ 	ext { towards west along the same road. If the distance towards cast is represented by a positive } \ 	ext { integer, then how will you represent the distance travelled towards west? By which integer } \ 	ext { will you represent her final position from } \mathrm{A} 	ext { ? }\end{array}\end{array} $$ (-20)-15

UpStudy AI · Accepted Answer

For part a) of the first question, we need to fill in the blank for $$ (-1) \times \_\_ $$. The answer is $$ (-1) $$ since $$ (-1) \times (-1) = 1 $$.

For part b), we calculate $$ (-1) \times (-25) $$:
$$
(-1) \times (-25) = 25
$$
So, the answer for part b) is $$ 25 $$.
For part a):
$$
2.3 - (-35) - 18 = 2.3 + 35 - 18 = 19.3
$$

For part b):
$$
39 + (-24) - 15 = 39 - 24 - 15 = 0
$$

Now we compare the results:
$$
19.3 \quad \text{and} \quad 0
$$
Thus, $$ 19.3 > 0 $$. The sign to fill in the box is $$ > $$.
Rita travels 20 km east and then 30 km west. We can represent east as a positive integer and west as a negative integer.

- Distance towards east: $$ +20 $$
- Distance towards west: $$ -30 $$

To find her final position from point A:
$$
\text{Final position} = 20 + (-30) = 20 - 30 = -10
$$
This means she is 10 km west of point A, which can be represented by the integer $$ -10 $$.
1. a) $$ (-1) $$ b) $$ 25 $$ 2. The sign is $$ > $$ 3. Distance towards west is represented by $$ -30 $$ and her final position from A is $$ -10 $$.

Fill in the blanks.
(-20)-15

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Fill in the blanks. (-20)-15