Cooper is studying two fractions that are both less than 1 . The first raction has a denominator of 4 and rounds to 1 . The second fraction las a denominator of 6 and the same numerator as the first fraction. s the second fraction closest to \( 1, \frac{1}{2} \) or 1 ? Explain.

Let's break down the problem step by step. 1. **Identify the first fraction**: - The first fraction has a denominator of 4 and rounds to 1. - Since it rounds to 1, it must be very close to 1, but still less than 1. The largest fraction with a denominator of 4 that is less than 1 is \( \frac{3}{4} \) (which is 0.75). The smallest fraction that rounds to 1 is \( \frac{4}{4} \) (which is 1), but since the fraction must be less than 1, we can conclude that the first fraction must be \( \frac{3}{4} \). 2. **Identify the second fraction**: - The second fraction has a denominator of 6 and the same numerator as the first fraction. - Since the first fraction is \( \frac{3}{4} \), the numerator for the second fraction is also 3. Therefore, the second fraction is \( \frac{3}{6} \). 3. **Simplify the second fraction**: - The second fraction \( \frac{3}{6} \) simplifies to \( \frac{1}{2} \). 4. **Compare the second fraction to 1, \( \frac{1}{2} \), and 1**: - The second fraction \( \frac{1}{2} \) is exactly equal to \( \frac{1}{2} \). - It is less than 1 and greater than \( \frac{1}{2} \). Now, we can conclude that the second fraction \( \frac{3}{6} \) is closest to \( \frac{1}{2} \). Thus, the answer is that the second fraction is closest to \( \frac{1}{2} \).