Question
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\( \begin{array}{ll}\text { 33. } 12=\frac{x}{7} & \text { 34. }-63=21 x \\ \text { 37. }-99=-11 a & \text { 38. } 4=\frac{b}{21}\end{array} \)

Ask by Smith Lawson. in the United States
Mar 15,2025

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Answer

**33. \(x = 84\)** **34. \(x = -3\)** **37. \(a = 9\)** **38. \(b = 84\)**

Solution

**33. Solve \(12 = \frac{x}{7}\)** Multiply both sides by 7 to isolate \(x\): \[ 12 \times 7 = \frac{x}{7} \times 7 \] \[ 84 = x \] Thus, \(x = 84\). **34. Solve \(-63 = 21x\)** Divide both sides by 21 to solve for \(x\): \[ x = \frac{-63}{21} \] \[ x = -3 \] **37. Solve \(-99 = -11a\)** Divide both sides by \(-11\) to isolate \(a\): \[ a = \frac{-99}{-11} \] \[ a = 9 \] **38. Solve \(4 = \frac{b}{21}\)** Multiply both sides by 21 to solve for \(b\): \[ 4 \times 21 = \frac{b}{21} \times 21 \] \[ 84 = b \] Thus, \(b = 84\).

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Beyond the Answer

To solve equation 33, you can multiply both sides by 7 to isolate x: \(12 \times 7 = x\). This gives you \(x = 84\). For equation 34, divide both sides by 21 to find x: \(x = -3\). So, for both equations, you have \(x = 84\) and \(x = -3\), respectively! Moving on to equation 37, divide both sides by -11 to find a: \(a = 9\). Finally, for equation 38, multiply both sides by 21 to solve for b: \(b = 84\). The results are \(a = 9\) and \(b = 84\). Math can be a real adventure when you break it down step by step!

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