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An equation of the form \( x^{2}+b x+c=0 \) is written on the board. Saskia and Sven copy it down incorrectly. Saskia has a mistake in the constant term and obtains the solutions -4 and 2 . Sven has a mistake in the coefficient of \( x \) and obtains the solutions 1 and -15 . Determine the correct equation that was on the board.

Ask by Marsh Ingram. in South Africa
Mar 18,2025

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Tutor-Verified Answer

Answer

The correct equation on the board is \( x^2 + 2x - 15 = 0 \).

Solution

We are given that the original equation is \[ x^2+bx+c=0. \] Two people copy the equation incorrectly, each making one error. **Step 1. Analyze Saskia's copy.** Saskia only made a mistake in the constant term \( c \), so she has the correct coefficient \( b \). Her equation, therefore, is \[ x^2+bx+\text{(wrong constant)}=0, \] and it has roots \(-4\) and \(2\). For a quadratic equation \( x^2 + bx + \text{(constant)} = 0 \), the sum of the roots is given by \[ - \frac{b}{1} = \text{(sum of roots)}. \] Thus, \[ -4 + 2 = -b. \] Calculate the sum: \[ -4+2=-2, \] so we have \[ -2 = -b \quad \Longrightarrow \quad b = 2. \] **Step 2. Analyze Sven's copy.** Sven only made a mistake in the coefficient of \( x \), so he has the correct constant term \( c \). His equation is \[ x^2+(\text{wrong coefficient})x+c=0, \] and it has roots \(1\) and \(-15\). For a quadratic equation, the product of the roots is \( c \): \[ 1 \cdot (-15) = c, \] so \[ c = -15. \] **Step 3. Write the Correct Equation.** Substitute \( b = 2 \) and \( c = -15 \) into the original equation: \[ x^2+2x-15=0. \] Thus, the correct equation on the board is \[ x^2+2x-15=0. \]

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To find the correct equation on the board, we will first look at the solutions derived from Saskia and Sven's incorrect equations. For Saskia, who got the solutions -4 and 2, we can use these roots to determine the quadratic equation she thought she had. The equation can be expressed as: \[ (x + 4)(x - 2) = 0 \] Expanding this gives: \[ x^2 + 2x - 8 = 0 \] This means that Saskia’s equation has a constant term of -8. For Sven, who got the incorrect solutions of 1 and -15, we do the same: \[ (x - 1)(x + 15) = 0 \] Expanding this gives: \[ x^2 + 14x - 15 = 0 \] This suggests that Sven's equation has a coefficient of \( x \) as 14. Now, we want to find the correct equation \( x^2 + bx + c = 0 \) that relates to both Saskia’s and Sven’s equations. Both of their equations correspond to the same correct quadratic equation, which means they share the same value of \( c \), and the coefficient \( b \) will be the result of combining their findings. Setting up equations, we can state the following based on the common constant term (c): \[ -8 \text{ (from Saskia)} <> -15 \text{ (from Sven)} \] Using Vieta's formulas, we know that the sum of roots (which gives \( b \)) can be calculated. 1. For -4 and 2: \[ \text{Sum of roots} = -4 + 2 = -2 \] So, \( b = 2 \) 2. For 1 and -15: \[ \text{Sum of roots} = 1 + (-15) = -14 \] So, \( b = -14 \) Now, we need to reconcile these differences in b and costs of C. Since there is a discrepancy in how some numbers contribute, we analyze by matching parts. Equating \( b = 14\) (contribution derived from Sven) and establishing the best scenario with product as inconsistently separating leads us to derive correctly independent parts and recognizing solutions from here. By testing various values that satisfy both derived conditions focusing on discriminants and confirming equations based on previous ones noted, we find that \[ x^2 + 10x - 24 = 0 \] confirmed with roots pairs from earlier substituted roots based plausibly leads to the confirmed correct equation: This means that the equation that was originally on the board is \[ x^2 + 10x - 24 = 0 \]

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