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Determine the vertex of the graph of the following parabola. \[ f(x)=-3(x-3)^{2}-2 \]

Ask by Estrada Fleming. in the United States
Feb 28,2025

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Answer

The vertex of the parabola is (3, -2).

Solution

The given quadratic function is already in vertex form, which is:   f(x) = a(x - h)² + k Comparing f(x) = -3(x - 3)² - 2 with the vertex form, we identify:   h = 3   k = -2 Therefore, the vertex of the parabola is (3, -2).

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The Deep Dive

The vertex of a parabola in the form \( f(x) = a(x-h)^2 + k \) is given by the point \( (h, k) \). In your equation, \( f(x) = -3(x-3)^2 - 2 \), we can identify \( h = 3 \) and \( k = -2 \). Therefore, the vertex of the graph is at the point \( (3, -2) \). Additionally, since the coefficient \( a = -3 \) is negative, the parabola opens downward, suggesting a maximum value at the vertex. This can be helpful when analyzing the function’s behavior, as it indicates that the vertex represents the highest point on the graph.

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