Use indirect reasoning to show that there is no whole number, \( n \), which solves the equation \( 6 n+14=31 \). Is the number 31 even or odd? odd even Is the number 14 even or odd? even odd Is the number \( 6 n \) even or odd? even Is the sum \( 6 n+14 \) even or odd? even odd
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To show that there is no whole number \( n \) which solves the equation \( 6n + 14 = 31 \) using indirect reasoning, we can start by examining the parity (evenness or oddness) of the numbers involved. Since 6n is even (as any multiple of 6 is), and 14 is also even, their sum \( 6n + 14 \) must be even. However, 31 is odd. Therefore, we reach a contradiction: an even number (left side) cannot equal an odd number (right side). This means there is no whole number \( n \) that satisfies the equation. Now let's recap the parity of the numbers: - The number 31 is **odd**. - The number 14 is **even**. - The number \( 6n \) is **even** since it's a multiple of 6 and any multiple of an even number is even. - The sum \( 6n + 14 \) is also **even**, as the sum of two even numbers remains even.