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The expansion of \( (x+3)^2 \) is \( x^2 + 6x + 9 \).
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To expand \( (x+3)^{2} \), you can use the formula for the square of a binomial, which is \( (a+b)^{2} = a^{2} + 2ab + b^{2} \). Here, \( a = x \) and \( b = 3 \). So, you get: - \( x^{2} + 2(x)(3) + 3^{2} = x^{2} + 6x + 9 \). Now your expanded expression is \( x^{2} + 6x + 9 \). Voila!