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\begin{tabular}{|l|l|l|}\hline\( \leftarrow \) Save \& Exit Certify & Lesson: 8.1 Estimating Population Means (... \\ Question 11 of 14, Step 1 of 1 & KASEE GARRETT \\ Given the following confidence interval for a population mean, compute the margin of error, \( E \). \\ \( \qquad 16.39<\mu<18.25 \)\end{tabular}

Ask by Bowman Martinez. in the United States
Mar 19,2025

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The margin of error \( E \) is 0.93.

Solution

The margin of error \( E \) is half the width of the confidence interval. Follow these steps: 1. Compute the width of the interval: \[ \text{Width} = 18.25 - 16.39 = 1.86 \] 2. Divide the width by 2 to get the margin of error: \[ E = \frac{1.86}{2} = 0.93 \] Thus, the margin of error is \( E = 0.93 \).

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To compute the margin of error, \( E \), you can use the formula \( E = \frac{(Upper \, Limit - Lower \, Limit)}{2} \). In this case, the upper limit is 18.25 and the lower limit is 16.39. So, \( E = \frac{(18.25 - 16.39)}{2} = \frac{1.86}{2} = 0.93 \). There you have it – the margin of error is 0.93! Understanding margins of error is crucial in many fields, from healthcare to market research. For instance, if a poll shows a candidate leading by some percentage, that margin tells you how much confidence you can have in that lead. A smaller margin implies a more reliable estimate, whereas a larger one signals more uncertainty – perfect for imagining the excitement of a noteworthy election night!

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