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A missile was fired from a submarine from 350 feet below sea level. If the missile reached a height of 10300 feet before exploding, what was the change in the altitude of the missile? Answer

Ask by Chang Phillips. in the United States
Jan 30,2025

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Answer

The missile's altitude increased by 10,650 feet.

Solution

To determine the change in altitude of the missile, we need to consider both the starting point (350 feet below sea level) and the highest point it reached (10,300 feet above sea level). 1. **Initial Altitude:** The missile starts **350 feet below sea level**, which can be represented as **-350 feet**. 2. **Final Altitude:** The missile reaches **10,300 feet above sea level**. **Change in Altitude** is calculated as: \[ \text{Change in Altitude} = \text{Final Altitude} - \text{Initial Altitude} \] \[ \text{Change in Altitude} = 10,300 \, \text{feet} - (-350 \, \text{feet}) = 10,300 \, \text{feet} + 350 \, \text{feet} = 10,650 \, \text{feet} \] **Therefore, the change in altitude of the missile is 10,650 feet.**

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To find the change in altitude of the missile, you can subtract the initial depth from the maximum height reached. The missile started at -350 feet (below sea level) and reached 10,300 feet (above sea level). So, the change in altitude is: 10,300 feet (above sea level) - (-350 feet) = 10,300 + 350 = 10,650 feet. Therefore, the change in altitude of the missile is 10,650 feet.

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