Question
What is the total amount of monthly payments for a \( \$ 6,100 \), two-year loan with an APR of \( 5 \% \) \( \$ 406.94 \) \( \$ 322.88 \) \( \$ 6,422.88 \) \( \$ 267.62 \)
Ask by Bowen West. in the United States
Mar 13,2025
Upstudy AI Solution
Tutor-Verified Answer
Answer
The total amount of monthly payments is \$6,422.88.
Solution
To find the total amount of monthly payments for a loan, we can use the formula for the monthly payment on an installment loan, which is given by:
\[
M = P \frac{r(1 + r)^n}{(1 + r)^n - 1}
\]
Where:
- \( M \) is the monthly payment
- \( P \) is the loan principal (amount borrowed)
- \( r \) is the monthly interest rate (annual interest rate divided by 12)
- \( n \) is the number of payments (loan term in months)
### Step 1: Extract known conditions
- Loan amount \( P = 6100 \)
- Annual interest rate \( APR = 5\% \)
- Loan term \( = 2 \) years \( = 24 \) months
### Step 2: Calculate the monthly interest rate
The monthly interest rate \( r \) is calculated as follows:
\[
r = \frac{APR}{12} = \frac{5\%}{12} = \frac{0.05}{12}
\]
### Step 3: Calculate the number of payments
The total number of payments \( n \) is:
\[
n = 2 \times 12 = 24
\]
### Step 4: Calculate the monthly payment \( M \)
Now we can substitute the values into the formula to find \( M \):
\[
M = 6100 \cdot \frac{\frac{0.05}{12}(1 + \frac{0.05}{12})^{24}}{(1 + \frac{0.05}{12})^{24} - 1}
\]
Let's calculate \( M \) using the above formula.
Calculate the value by following steps:
- step0: Calculate:
\(\frac{6100\left(\frac{0.05}{12}\left(1+\frac{0.05}{12}\right)^{24}\right)}{\left(\left(1+\frac{0.05}{12}\right)^{24}-1\right)}\)
- step1: Remove the parentheses:
\(\frac{6100\times \frac{0.05}{12}\left(1+\frac{0.05}{12}\right)^{24}}{\left(1+\frac{0.05}{12}\right)^{24}-1}\)
- step2: Divide the terms:
\(\frac{6100\times \frac{0.05}{12}\left(1+\frac{1}{240}\right)^{24}}{\left(1+\frac{0.05}{12}\right)^{24}-1}\)
- step3: Add the numbers:
\(\frac{6100\times \frac{0.05}{12}\left(\frac{241}{240}\right)^{24}}{\left(1+\frac{0.05}{12}\right)^{24}-1}\)
- step4: Divide the terms:
\(\frac{6100\times \frac{0.05}{12}\left(\frac{241}{240}\right)^{24}}{\left(1+\frac{1}{240}\right)^{24}-1}\)
- step5: Add the numbers:
\(\frac{6100\times \frac{0.05}{12}\left(\frac{241}{240}\right)^{24}}{\left(\frac{241}{240}\right)^{24}-1}\)
- step6: Divide the terms:
\(\frac{6100\times \frac{1}{240}\left(\frac{241}{240}\right)^{24}}{\left(\frac{241}{240}\right)^{24}-1}\)
- step7: Multiply:
\(\frac{\frac{61\times 241^{24}}{12\times 5^{23}\times 48^{24}}}{\left(\frac{241}{240}\right)^{24}-1}\)
- step8: Subtract the numbers:
\(\frac{\frac{61\times 241^{24}}{12\times 5^{23}\times 48^{24}}}{\frac{241^{24}-240^{24}}{240^{24}}}\)
- step9: Multiply by the reciprocal:
\(\frac{61\times 241^{24}}{12\times 5^{23}\times 48^{24}}\times \frac{240^{24}}{241^{24}-240^{24}}\)
- step10: Rewrite the expression:
\(\frac{61\times 241^{24}}{12\times 5^{23}\times 48^{24}}\times \frac{12^{24}\times 20^{24}}{241^{24}-240^{24}}\)
- step11: Reduce the numbers:
\(\frac{61\times 241^{24}}{5^{23}\times 48^{24}}\times \frac{12^{23}\times 20^{24}}{241^{24}-240^{24}}\)
- step12: Rewrite the expression:
\(\frac{61\times 241^{24}}{5^{23}\times 12^{24}\times 4^{24}}\times \frac{12^{23}\times 20^{24}}{241^{24}-240^{24}}\)
- step13: Reduce the numbers:
\(\frac{61\times 241^{24}}{5^{23}\times 12\times 4^{24}}\times \frac{20^{24}}{241^{24}-240^{24}}\)
- step14: Rewrite the expression:
\(\frac{61\times 241^{24}}{5^{23}\times 12\times 4^{24}}\times \frac{5^{24}\times 4^{24}}{241^{24}-240^{24}}\)
- step15: Reduce the numbers:
\(\frac{61\times 241^{24}}{12\times 4^{24}}\times \frac{5\times 4^{24}}{241^{24}-240^{24}}\)
- step16: Rewrite the expression:
\(\frac{61\times 241^{24}}{4\times 3\times 4^{24}}\times \frac{5\times 4^{24}}{241^{24}-240^{24}}\)
- step17: Reduce the numbers:
\(\frac{61\times 241^{24}}{3\times 4}\times \frac{5}{241^{24}-240^{24}}\)
- step18: Multiply the fractions:
\(\frac{61\times 241^{24}\times 5}{12\left(241^{24}-240^{24}\right)}\)
- step19: Multiply:
\(\frac{305\times 241^{24}}{12\times 241^{24}-12\times 240^{24}}\)
The calculated monthly payment \( M \) is approximately \( 267.62 \).
### Step 5: Calculate the total amount of monthly payments
To find the total amount of monthly payments over the loan term, we multiply the monthly payment by the number of payments:
\[
\text{Total Payments} = M \times n = 267.62 \times 24
\]
Now, let's calculate the total amount of monthly payments.
Calculate the value by following steps:
- step0: Calculate:
\(267.62\times 24\)
- step1: Multiply the numbers:
\(6422.88\)
The total amount of monthly payments over the two-year loan is \( 6422.88 \).
### Summary of Results
- Monthly Payment: \( 267.62 \)
- Total Amount of Monthly Payments: \( 6422.88 \)
Thus, the correct answer is \( \$ 6,422.88 \).
Answered by UpStudy AI and reviewed by a Professional Tutor
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Mind Expander
To calculate the total monthly payments for a loan, we can use the formula for a fixed-rate mortgage or loan payment calculation. In this case, with a principal amount of \( \$ 6,100 \), an APR of \( 5\% \), and a loan term of 24 months, the monthly payment can be calculated using a financial calculator or appropriate software. Assuming a monthly payment of approximately \( \$ 267.62 \), the total amount paid over two years would then be \( 267.62 \times 24 = \$ 6,422.88 \). So the total monthly payments lead us to the third option listed above!