Question
Multiply the expressions. Part 1 of 3 (a) \( (\sqrt{3}+\sqrt{q})(\sqrt{3}+\sqrt{q})=\square \)
Ask by Chandler Herrera. in the United States
Dec 03,2024
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Answer
\( 3+2\sqrt{3q}+q \)
Solution
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Bonus Knowledge
When you multiply the expression \( (\sqrt{3}+\sqrt{q})(\sqrt{3}+\sqrt{q}) \), you're essentially squaring a binomial. Using the formula \((a + b)^2 = a^2 + 2ab + b^2\), we get: \[ = (\sqrt{3})^2 + 2(\sqrt{3})(\sqrt{q}) + (\sqrt{q})^2 = 3 + 2\sqrt{3q} + q. \] So the expression simplifies to \( 3 + 2\sqrt{3q} + q \).