Question
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Which of the following word problems can be solved using the equation \( 10 x-15=60 \) ? Select two that apply. A. Kit buys 10 packages of batteries. After using a \( \$ 15 \) coupon, the batteries cost \( \$ 60 \). What was the original price, \( x \), in dollars, of each package of batteries? \( \square \) B. Ursula bought 10 calculators at a store and paid \( \$ 60 \). Each calculator was on sale for \( \$ 15 \) off. What was the original price, \( x \), in dollars, of each calculator? C. Siobhan originally has \( \$ 15 \). After working as a waiter in a restaurant for \( \$ 10 \) an hour, he now has \( \$ 60 \). How many hours, \( x \), did Siobhan work at the restaurant? D. Gary worked for 10 hours tutoring students at the library. He uses \( \$ 15 \) to pay for gas on his way home. If he has \( \$ 60 \) left after paying for gas, how much money, \( x \), in dollars, was Gary paid per hour?

Ask by Joseph Boyd. in the United States
Mar 11,2025

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Answer

Options A and D can be solved using the equation \(10x - 15 = 60\).

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The Deep Dive

The equation \( 10x - 15 = 60 \) perfectly fits option A, where Kit buys 10 packages of batteries, and after using a $15 coupon, the total cost is $60. We can set up the equation since \( 10x \) represents the total cost before the coupon, and subtracting $15 gives the final price. Option D also aligns well with the equation, as Gary works 10 hours and pays $15 for gas, leaving him with $60. The setup \( 10x - 15 = 60 \) represents his earnings from tutoring after his gas expenses. Both options cleverly illustrate how to apply algebra in practical, everyday scenarios!

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