Question
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9. A car moving at a constant speed passes a timing device at \( t=0 \). After 8 seconds, the car has traveled 840 feet. What linear function in the form \( y=m x+b \) represents the distance in feet, \( d \), the car has traveled any number of seconds, \( t \), after passing the timing device?

Ask by Logan Campos. in the United States
Mar 12,2025

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Tutor-Verified Answer

Answer

The distance \( d \) in feet after \( t \) seconds is given by \( d = 105t \).

Solution

Let \( t \) represent time in seconds and \( d \) represent distance in feet. 1. At \( t=0 \), the car is at the timing device, so \( d=0 \). This gives the point \( (0,0) \). 2. At \( t=8 \) seconds, the car has traveled 840 feet, giving the point \( (8,840) \). 3. The slope \( m \) of the line is calculated by: \[ m = \frac{840-0}{8-0}=\frac{840}{8}=105. \] 4. Since the car starts at the timing device, the \( y \)-intercept \( b \) is 0. Thus, the linear function that represents the distance in feet as a function of time in seconds is: \[ d =105t. \]

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Mind Expander

To find the linear function representing the distance \( d \) traveled by the car over time \( t \), we first determine the slope \( m \). The car travels 840 feet in 8 seconds, so the slope is: \[ m = \frac{d}{t} = \frac{840 \text{ feet}}{8 \text{ seconds}} = 105 \text{ feet/second}. \] Since the car starts from the timing device (which we can consider as 0 feet at \( t=0 \)), the y-intercept \( b \) is 0. Putting it all together, the linear function is: \[ d(t) = 105t + 0 \] or simply \[ d(t) = 105t. \] This function shows how the distance varies linearly with time! Now, remember that this represents constant speed, which is why we have a straight line. The distance increases uniformly—just like that time you drove down a flat road at the same speed and felt like a racing champion!

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