Question
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following by rationalizing the denominator and reducing, if necessal \[ \frac{48}{5+\sqrt{13}} \]

Ask by Stuart Curry. in the United States
Mar 01,2025

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Tutor-Verified Answer

Answer

The simplified form is \(20 - 4\sqrt{13}\).

Solution

Calculate or simplify the expression \( \frac{48}{5+\sqrt{13}} \). Calculate the value by following steps: - step0: Calculate: \(\frac{48}{5+\sqrt{13}}\) - step1: Multiply by the Conjugate: \(\frac{48\left(5-\sqrt{13}\right)}{\left(5+\sqrt{13}\right)\left(5-\sqrt{13}\right)}\) - step2: Multiply the numbers: \(\frac{48\left(5-\sqrt{13}\right)}{12}\) - step3: Factor the expression: \(\frac{4\left(5-\sqrt{13}\right)\times 12}{12}\) - step4: Reduce the fraction: \(4\left(5-\sqrt{13}\right)\) - step5: Apply the distributive property: \(4\times 5-4\sqrt{13}\) - step6: Multiply the numbers: \(20-4\sqrt{13}\) The rationalized form of the given expression \(\frac{48}{5+\sqrt{13}}\) after rationalizing the denominator and reducing is \(20-4\sqrt{13}\).

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The Deep Dive

To rationalize the denominator of the expression \(\frac{48}{5+\sqrt{13}}\), we multiply the numerator and the denominator by the conjugate of the denominator, which is \(5 - \sqrt{13}\): \[ \frac{48(5 - \sqrt{13})}{(5 + \sqrt{13})(5 - \sqrt{13})} \] Calculating the denominator: \[ (5 + \sqrt{13})(5 - \sqrt{13}) = 5^2 - (\sqrt{13})^2 = 25 - 13 = 12 \] Now calculate the numerator: \[ 48(5 - \sqrt{13}) = 240 - 48\sqrt{13} \] Putting it all together, we have: \[ \frac{240 - 48\sqrt{13}}{12} \] Next, we can simplify this by dividing both terms in the numerator by 12: \[ \frac{240}{12} - \frac{48\sqrt{13}}{12} = 20 - 4\sqrt{13} \] Thus, the final simplified expression is: \[ 20 - 4\sqrt{13} \]

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