t) \( 843 \div 6 \)

To solve \( 843 \div 6 \), you can approach it with long division. First, see how many times 6 goes into 84 (the first two digits); it goes 14 times (since \( 6 \times 14 = 84 \)). Bring down the next digit, which is 3, making it 3. Now, 6 goes 0 times into 3, so the remainder is 3. Therefore, \( 843 \div 6 = 140\) with a remainder of 3, or expressed as \( 140\frac{3}{6}\), which simplifies to \( 140\frac{1}{2}\). If you need to do it quickly in real life, you can break it down: Recognize that 840 is friendly with 6 because \( 840 \div 6 = 140\) and then just deal with the extra 3. So, keep it cool, take the whole numbers, and round it out!