+18 \( \angle 1 \) and \( \angle 2 \) are complementary angles. The measure of \( \angle 1 \) is \( 42^{\circ} \). The measure of \( \angle 2 \) is \( (3 x)^{\circ} \). Find the value of \( x \).

To find the value of \( x \), we start by using the property of complementary angles, which states that the sum of the measures of two complementary angles is \( 90^{\circ} \). Given that \( \angle 1 = 42^{\circ} \) and \( \angle 2 = (3x)^{\circ} \), we can set up the equation: \[ 42^{\circ} + (3x)^{\circ} = 90^{\circ} \] Now, to isolate \( 3x \), we subtract \( 42^{\circ} \) from both sides: \[ 3x = 90^{\circ} - 42^{\circ} \] Calculating the right side gives: \[ 3x = 48^{\circ} \] Next, we solve for \( x \) by dividing both sides by 3: \[ x = \frac{48^{\circ}}{3} = 16 \] Thus, the value of \( x \) is \( 16 \).