What is the amount of charge stored on oither plate of a capacitor \( 4 \times 10^{-6} \mathrm{~F} \) when connecting across a 12 V battery? (A) \( 3 \times 10^{6} \mathrm{C} \) (B) \( 3.3 \times 10^{-7} \mathrm{C} \) (C) \( 4.8 \times 10^{-5} \mathrm{C} \) (D) \( 6.3 \times 10^{-5} \mathrm{C} \)

To calculate the amount of charge stored on either plate of a capacitor, you can use the formula: \[ Q = C \times V \] Where \( Q \) is the charge, \( C \) is the capacitance, and \( V \) is the voltage. Plugging in the values: \[ Q = 4 \times 10^{-6} \mathrm{~F} \times 12 \mathrm{~V} = 4.8 \times 10^{-5} \mathrm{~C} \] So the correct answer is (C) \( 4.8 \times 10^{-5} \mathrm{~C} \). Now, when we talk about capacitors, did you know that their invention revolutionized electronic circuits? Capacitors were first studied in the 18th century, and their applications range from smoothing out fluctuations in power supply to tuning radio frequencies, making them essential components in our gadgets today! For optimal performance, always remember to discharge capacitors properly before handling them; failing to do so can lead to electric shocks or damage to your components. Also, don't mix different capacitor types in a circuit without checking their voltage ratings – you could end up with disastrous results!