Question

22) \( 7 a^{2}-11 a+4 \)

Ask by Wade Brewer. in the United States
Mar 12,2025

Upstudy AI Solution

Tutor-Verified Answer

Answer

The quadratic \(7a^{2} -11a +4\) factors to \((a-1)(7a-4)\).

Solution

1. Multiply the coefficient of \( a^2 \) (which is \(7\)) by the constant term (which is \(4\)) to obtain: \[ 7 \times 4 = 28. \] 2. Find two numbers that multiply to \(28\) and add to \(-11\) (the coefficient of \(a\)). The two numbers are \(-7\) and \(-4\) because: \[ (-7)(-4) = 28 \quad \text{and} \quad (-7) + (-4) = -11. \] 3. Rewrite the quadratic by splitting the middle term: \[ 7a^2 -11a +4 = 7a^2 -7a -4a +4. \] 4. Factor by grouping: - Group the terms: \[ (7a^2 -7a) + (-4a +4). \] - Factor out the common factor from each group: \[ 7a(a-1) -4(a-1). \] 5. Factor out the common binomial factor \((a-1)\): \[ (a-1)(7a-4). \] Thus, the factorization is: \[ (a-1)(7a-4). \]

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Extra Insights

Did you know that quadratic expressions like \( 7a^{2}-11a+4 \) can often be solved using the quadratic formula \( a = \frac{-b \pm \sqrt{b^2-4ac}}{2a} \)? Here, 'a', 'b', and 'c' correspond to the coefficients in our polynomial. So for our expression, \( a = 7 \), \( b = -11 \), and \( c = 4 \). Quick math can lead you to the roots of this beautiful equation! If you're feeling adventurous, you can also factor quadratic expressions! For \( 7a^2 - 11a + 4 \), look for two numbers that multiply to \( 7 \cdot 4 = 28 \) and add up to \(-11\). It can be tricky, but remember that quadratic equations have real-world applications like projectile motion and calculating profit margins, making mastering these equations super beneficial in everyday scenarios!

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