Graph the following equation by plotting two points. $$ y+3=\frac{2}{7}(x-2) $$

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1. Start with the given equation in point–slope form:
   $$
   y + 3 = \frac{2}{7}(x - 2)
   $$
   
2. Identify the fixed point and the slope.  
   From the equation, the line passes through the point  
   $$
   (2, -3)
   $$
   and has a slope of  
   $$
   m = \frac{2}{7}.
   $$
   
3. To plot two points, use the known point and find another point by using the slope.  
   Since the slope is $$\frac{2}{7}$$, it means that for an increase of $$7$$ in $$x$$, $$y$$ increases by $$2$$.  
   Starting from $$(2,-3)$$:
   - Increase $$x$$ by $$7$$: $$x = 2 + 7 = 9$$.  
     Then,
     $$
     y = -3 + 2 = -1.
     $$
   So, the second point is $$(9, -1)$$.

4. Alternatively, you can verify by converting the equation to slope–intercept form:
   $$
   y + 3 = \frac{2}{7}(x - 2) \quad \Rightarrow \quad y = \frac{2}{7}x - \frac{4}{7} - 3.
   $$
   Express $$-3$$ as $$-\frac{21}{7}$$:
   $$
   y = \frac{2}{7}x - \frac{4}{7} - \frac{21}{7} = \frac{2}{7}x - \frac{25}{7}.
   $$
   The y-intercept is $$\left(0, -\frac{25}{7}\right)$$. However, plotting $$(2,-3)$$ and $$(9,-1)$$ from the step–slope form is generally simpler.

5. Finally, plot the points $$(2, -3)$$ and $$(9, -1)$$ on a coordinate plane and draw a straight line through them, which represents the graph of the equation.

Thus, the two points to plot are:
$$
(2, -3) \quad \text{and} \quad (9, -1).
$$
Plot the points (2, -3) and (9, -1) on a coordinate plane and draw a straight line through them.

Graph the following equation by plotting two points.

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