Answer
For Expression 5.2.5, the result is \(-1\).
For Expression 5.2.6, the result is \(-\tan(\beta)\).
Solution
Simplify the expression by following steps:
- step0: Solution:
\(\frac{\sin\left(\beta -180^{\circ}\right)\tan\left(-\beta -180^{\circ}\right)\cos\left(180^{\circ}+\beta \right)}{\cos\left(-\beta \right)\sin\left(360^{\circ}+\beta \right)}\)
- step1: Rewrite the expression:
\(\frac{-\sin\left(\beta \right)\tan\left(-\beta -180^{\circ}\right)\cos\left(180^{\circ}+\beta \right)}{\cos\left(-\beta \right)\sin\left(360^{\circ}+\beta \right)}\)
- step2: Rewrite the expression:
\(\frac{-\sin\left(\beta \right)\left(-\tan\left(\beta \right)\right)\cos\left(180^{\circ}+\beta \right)}{\cos\left(-\beta \right)\sin\left(360^{\circ}+\beta \right)}\)
- step3: Rewrite the expression:
\(\frac{-\sin\left(\beta \right)\left(-\tan\left(\beta \right)\right)\left(-\cos\left(\beta \right)\right)}{\cos\left(-\beta \right)\sin\left(360^{\circ}+\beta \right)}\)
- step4: Transform the expression:
\(\frac{-\sin\left(\beta \right)\left(-\tan\left(\beta \right)\right)\left(-\cos\left(\beta \right)\right)}{\cos\left(\beta \right)\sin\left(360^{\circ}+\beta \right)}\)
- step5: Rewrite the expression:
\(\frac{-\sin\left(\beta \right)\left(-\tan\left(\beta \right)\right)\left(-\cos\left(\beta \right)\right)}{\cos\left(\beta \right)\sin\left(\beta \right)}\)
- step6: Reduce the fraction:
\(-\frac{\sin\left(\beta \right)\left(-\tan\left(\beta \right)\right)\left(-\cos\left(\beta \right)\right)}{\cos\left(\beta \right)\sin\left(\beta \right)}\)
- step7: Reduce the fraction:
\(-\frac{-\tan\left(\beta \right)\left(-\cos\left(\beta \right)\right)}{\cos\left(\beta \right)}\)
- step8: Factor:
\(-\frac{-\tan\left(\beta \right)\left(-\cos\left(\beta \right)\right)}{\cos\left(\beta \right)\times 1}\)
- step9: Factor the expression:
\(-\frac{-\tan\left(\beta \right)\left(-1\right)\cos\left(\beta \right)}{\cos\left(\beta \right)}\)
- step10: Reduce the fraction:
\(-\left(-\tan\left(\beta \right)\left(-1\right)\right)\)
- step11: Calculate:
\(-\tan\left(\beta \right)\)
Calculate or simplify the expression \( \frac { \cos ( \alpha - 90 ^ { \circ } ) \cdot \tan ( - \alpha ) } { \sin ( - \alpha ) \cdot \tan ( 720 ^ { \circ } - \alpha ) } \).
Simplify the expression by following steps:
- step0: Solution:
\(\frac{\cos\left(\alpha -90^{\circ}\right)\tan\left(-\alpha \right)}{\sin\left(-\alpha \right)\tan\left(720^{\circ}-\alpha \right)}\)
- step1: Rewrite the expression:
\(\frac{\sin\left(\alpha \right)\tan\left(-\alpha \right)}{\sin\left(-\alpha \right)\tan\left(720^{\circ}-\alpha \right)}\)
- step2: Transform the expression:
\(\frac{\sin\left(\alpha \right)\left(-\tan\left(\alpha \right)\right)}{\sin\left(-\alpha \right)\tan\left(720^{\circ}-\alpha \right)}\)
- step3: Transform the expression:
\(\frac{\sin\left(\alpha \right)\left(-\tan\left(\alpha \right)\right)}{-\sin\left(\alpha \right)\tan\left(720^{\circ}-\alpha \right)}\)
- step4: Rewrite the expression:
\(\frac{\sin\left(\alpha \right)\left(-\tan\left(\alpha \right)\right)}{-\sin\left(\alpha \right)\left(-\tan\left(\alpha \right)\right)}\)
- step5: Reduce the fraction:
\(-\frac{\sin\left(\alpha \right)\left(-\tan\left(\alpha \right)\right)}{\sin\left(\alpha \right)\left(-\tan\left(\alpha \right)\right)}\)
- step6: Reduce the fraction:
\(-1\)
Let's break down the two expressions step by step.
### Expression 5.2.5
The expression is:
\[
\frac { \cos ( \alpha - 90 ^ { \circ } ) \cdot \tan ( - \alpha ) } { \sin ( - \alpha ) \cdot \tan ( 720 ^ { \circ } - \alpha ) }
\]
1. **Simplifying \( \cos ( \alpha - 90^\circ ) \)**:
\[
\cos ( \alpha - 90^\circ ) = \sin(\alpha)
\]
2. **Simplifying \( \tan(-\alpha) \)**:
\[
\tan(-\alpha) = -\tan(\alpha)
\]
3. **Simplifying \( \sin(-\alpha) \)**:
\[
\sin(-\alpha) = -\sin(\alpha)
\]
4. **Simplifying \( \tan(720^\circ - \alpha) \)**:
\[
\tan(720^\circ - \alpha) = \tan(-\alpha) = -\tan(\alpha)
\]
Now substituting these simplifications back into the expression:
\[
\frac { \sin(\alpha) \cdot (-\tan(\alpha)) } { -\sin(\alpha) \cdot (-\tan(\alpha)) }
\]
This simplifies to:
\[
\frac { \sin(\alpha) \cdot \tan(\alpha) } { \sin(\alpha) \cdot \tan(\alpha) } = -1
\]
### Expression 5.2.6
The expression is:
\[
\frac { \sin ( \beta - 180 ^ { \circ } ) \cdot \tan ( - \beta - 180 ^ { \circ } ) \cdot \cos ( 180 ^ { \circ } + \beta ) } { \cos ( - \beta ) \cdot \sin ( 360 ^ { \circ } + \beta ) }
\]
1. **Simplifying \( \sin ( \beta - 180^\circ ) \)**:
\[
\sin ( \beta - 180^\circ ) = -\sin(\beta)
\]
2. **Simplifying \( \tan(-\beta - 180^\circ) \)**:
\[
\tan(-\beta - 180^\circ) = \tan(-\beta) = -\tan(\beta)
\]
3. **Simplifying \( \cos(180^\circ + \beta) \)**:
\[
\cos(180^\circ + \beta) = -\cos(\beta)
\]
4. **Simplifying \( \cos(-\beta) \)**:
\[
\cos(-\beta) = \cos(\beta)
\]
5. **Simplifying \( \sin(360^\circ + \beta) \)**:
\[
\sin(360^\circ + \beta) = \sin(\beta)
\]
Now substituting these simplifications back into the expression:
\[
\frac { (-\sin(\beta)) \cdot (-\tan(\beta)) \cdot (-\cos(\beta)) } { \cos(\beta) \cdot \sin(\beta) }
\]
This simplifies to:
\[
\frac { \sin(\beta) \cdot \tan(\beta) \cdot \cos(\beta) } { \cos(\beta) \cdot \sin(\beta) } = -\tan(\beta)
\]
### Final Results
- For Expression 5.2.5: The result is \(-1\).
- For Expression 5.2.6: The result is \(-\tan(\beta)\).
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