Question

2. Scate the divisibitity tests for 3. 5 and 9 with an example for each.

Ask by Garrett Ingram. in Australia
Mar 18,2025

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Answer

- **Divisible by 3:** If the sum of the digits is divisible by 3 (e.g., 123). - **Divisible by 5:** If the number ends with 0 or 5 (e.g., 45). - **Divisible by 9:** If the sum of the digits is divisible by 9 (e.g., 729).

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The Deep Dive

To test for divisibility by 3, simply add up all the digits in the number and check if that sum is divisible by 3. For example, take the number 123: 1 + 2 + 3 = 6, which is divisible by 3, so 123 is also divisible by 3! For divisibility by 5, look at the last digit of the number. If it’s a 0 or a 5, the number is divisible by 5. Consider the number 145: since it ends in 5, we can confidently say that 145 is divisible by 5! When it comes to divisibility by 9, you again add all the digits of the number. If that total can be divided evenly by 9, then your number also is. For instance, with the number 234: 2 + 3 + 4 = 9, which is divisible by 9, proving that 234 is divisible by 9 too!

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