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11. Higher Order Thinking Phil baked two kinds of pies. Each pie pan was the same size. He served \( \frac{1}{2} \) of the blueberry pie. He served \( \frac{1}{4} \) of the apple pie. If each pie had 8 pieces to start, what fraction in eighths of the apple pie did he serve? How many more pieces of the blueberry pie than the apple pie did he serve?

Ask by Schofield Lindsey. in the United States
Mar 18,2025

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Answer

Phil served \( \frac{2}{8} \) of the apple pie and 2 more pieces of blueberry pie than apple pie.

Solution

1. For the apple pie, Phil served a fraction of \( \frac{1}{4} \). Since the apple pie originally had 8 pieces, the number of pieces served is \[ \frac{1}{4} \times 8 = 2 \text{ pieces}. \] Expressing this as a fraction in eighths gives \[ \frac{2}{8}. \] 2. For the blueberry pie, Phil served a fraction of \( \frac{1}{2} \). With 8 pieces in the blueberry pie, the number of pieces served is \[ \frac{1}{2} \times 8 = 4 \text{ pieces}. \] Therefore, the number of more pieces of blueberry pie served than apple pie is \[ 4 - 2 = 2 \text{ pieces}. \]

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Phil started with 8 pieces of each pie. When he served \( \frac{1}{2} \) of the blueberry pie, that means he served \( \frac{1}{2} \times 8 = 4 \) pieces of blueberry pie. For the apple pie, he served \( \frac{1}{4} \) of it, which is \( \frac{1}{4} \times 8 = 2 \) pieces. To express the pieces of the apple pie served in eighths, we convert it: \( 2 \) pieces is equivalent to \( \frac{2}{8} \) in eighths. Therefore, he served \( \frac{2}{8} \) of the apple pie. Now, calculate the difference in the number of pieces served: 4 pieces (blueberry) - 2 pieces (apple) = 2 pieces. Thus, he served 2 more pieces of the blueberry pie than the apple pie.

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