Answer
The simplified expression is \( \frac{4m + 28}{m^{2} + 6m + 5} \).
Solution
Simplify the expression by following steps:
- step0: Solution:
\(\frac{8}{m^{2}+6m+5}+\frac{4}{m+1}\)
- step1: Factor the expression:
\(\frac{8}{\left(m+5\right)\left(m+1\right)}+\frac{4}{m+1}\)
- step2: Reduce fractions to a common denominator:
\(\frac{8}{\left(m+5\right)\left(m+1\right)}+\frac{4\left(m+5\right)}{\left(m+1\right)\left(m+5\right)}\)
- step3: Rewrite the expression:
\(\frac{8}{\left(m+5\right)\left(m+1\right)}+\frac{4\left(m+5\right)}{\left(m+5\right)\left(m+1\right)}\)
- step4: Transform the expression:
\(\frac{8+4\left(m+5\right)}{\left(m+5\right)\left(m+1\right)}\)
- step5: Multiply the terms:
\(\frac{8+4m+20}{\left(m+5\right)\left(m+1\right)}\)
- step6: Add the numbers:
\(\frac{28+4m}{\left(m+5\right)\left(m+1\right)}\)
- step7: Multiply the terms:
\(\frac{28+4m}{m^{2}+6m+5}\)
To simplify the expression \( \frac{8}{m^{2}+6 m+5}+\frac{4}{m+1} \), we follow these steps:
1. **Identify the denominators**: The first term has a denominator of \( m^{2}+6m+5 \) and the second term has a denominator of \( m+1 \).
2. **Factor the first denominator**: The quadratic \( m^{2}+6m+5 \) can be factored as \( (m+1)(m+5) \).
3. **Rewrite the expression**: The expression can now be rewritten as:
\[
\frac{8}{(m+1)(m+5)} + \frac{4}{m+1}
\]
4. **Find a common denominator**: The common denominator for both fractions is \( (m+1)(m+5) \).
5. **Rewrite the second term**: The second term can be rewritten to have the common denominator:
\[
\frac{4(m+5)}{(m+1)(m+5)}
\]
6. **Combine the fractions**:
\[
\frac{8 + 4(m+5)}{(m+1)(m+5)} = \frac{8 + 4m + 20}{(m+1)(m+5)} = \frac{4m + 28}{(m+1)(m+5)}
\]
Thus, the simplified expression is:
\[
\frac{4m + 28}{m^{2} + 6m + 5}
\]
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