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\( 1.1 .2 \frac { ( 3 c i s 23 ^ { \circ } ) ( 4 c i s 7 ^ { \circ } ) } { ( c i s 15 ^ { \circ } ) ( 6 c i s 5 ^ { \circ } ) } \)

Ask by Munoz Floyd. in South Africa
Mar 12,2025

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Tutor-Verified Answer

Answer

The simplified expression is \(4.4 \text{cis}(10^\circ)\).

Solution

To simplify the expression \[ 1.1 \cdot 2 \cdot \frac{(3 \text{cis} 23^\circ)(4 \text{cis} 7^\circ)}{(\text{cis} 15^\circ)(6 \text{cis} 5^\circ)} \] we will follow these steps: 1. **Multiply the constants and the cis terms in the numerator.** 2. **Multiply the constants and the cis terms in the denominator.** 3. **Divide the results from step 1 by the results from step 2.** 4. **Combine the results with the constant factor \(1.1 \cdot 2\).** ### Step 1: Multiply the constants and the cis terms in the numerator The numerator is: \[ (3 \text{cis} 23^\circ)(4 \text{cis} 7^\circ) = 3 \cdot 4 \cdot \text{cis}(23^\circ + 7^\circ) = 12 \text{cis}(30^\circ) \] ### Step 2: Multiply the constants and the cis terms in the denominator The denominator is: \[ (\text{cis} 15^\circ)(6 \text{cis} 5^\circ) = 6 \cdot \text{cis}(15^\circ + 5^\circ) = 6 \text{cis}(20^\circ) \] ### Step 3: Divide the results from step 1 by the results from step 2 Now we have: \[ \frac{12 \text{cis}(30^\circ)}{6 \text{cis}(20^\circ)} = \frac{12}{6} \cdot \text{cis}(30^\circ - 20^\circ) = 2 \text{cis}(10^\circ) \] ### Step 4: Combine the results with the constant factor \(1.1 \cdot 2\) Now we multiply by \(1.1 \cdot 2\): \[ 1.1 \cdot 2 \cdot 2 \text{cis}(10^\circ) = 2.2 \cdot 2 \text{cis}(10^\circ) = 4.4 \text{cis}(10^\circ) \] ### Final Result Thus, the simplified expression is: \[ 4.4 \text{cis}(10^\circ) \]

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To simplify the expression \( 1.1 .2 \frac { ( 3 c i s 23 ^ { \circ } ) ( 4 c i s 7 ^ { \circ } ) } { ( c i s 15 ^ { \circ } ) ( 6 c i s 5 ^ { \circ } ) } \), we start by multiplying the factors in the numerator and denominator. 1. **Numerator**: \[ (3 c i s 23^\circ)(4 c i s 7^\circ) = 12 c i s (23^\circ + 7^\circ) = 12 c i s 30^\circ. \] 2. **Denominator**: \[ (c i s 15^\circ)(6 c i s 5^\circ) = 6 c i s (15^\circ + 5^\circ) = 6 c i s 20^\circ. \] Putting it all together: \[ 1.1 .2 \frac{ 12 c i s 30^\circ }{ 6 c i s 20^\circ }. \] Now simplify: \[ = 1.1 .2 \cdot 2 \cdot \frac{c i s 30^\circ}{c i s 20^\circ}. \] The \( c i s \) notation is equivalent to the complex exponential, so we can further express this as: \[ = 1.1 .2 \cdot 2 \cdot c i s (30^\circ - 20^\circ) = 1.1 .2 \cdot 2 \cdot c i s 10^\circ. \] Putting the numbers together: \[ 1.1 \cdot 0.2 \cdot 2 = 0.44. \] Thus, our final result is: \[ 0.44 c i s 10^\circ. \]

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