\( 1.1 .2 \frac { ( 3 c i s 23 ^ { \circ } ) ( 4 c i s 7 ^ { \circ } ) } { ( c i s 15 ^ { \circ } ) ( 6 c i s 5 ^ { \circ } ) } \)
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To simplify the expression \( 1.1 .2 \frac { ( 3 c i s 23 ^ { \circ } ) ( 4 c i s 7 ^ { \circ } ) } { ( c i s 15 ^ { \circ } ) ( 6 c i s 5 ^ { \circ } ) } \), we start by multiplying the factors in the numerator and denominator. 1. **Numerator**: \[ (3 c i s 23^\circ)(4 c i s 7^\circ) = 12 c i s (23^\circ + 7^\circ) = 12 c i s 30^\circ. \] 2. **Denominator**: \[ (c i s 15^\circ)(6 c i s 5^\circ) = 6 c i s (15^\circ + 5^\circ) = 6 c i s 20^\circ. \] Putting it all together: \[ 1.1 .2 \frac{ 12 c i s 30^\circ }{ 6 c i s 20^\circ }. \] Now simplify: \[ = 1.1 .2 \cdot 2 \cdot \frac{c i s 30^\circ}{c i s 20^\circ}. \] The \( c i s \) notation is equivalent to the complex exponential, so we can further express this as: \[ = 1.1 .2 \cdot 2 \cdot c i s (30^\circ - 20^\circ) = 1.1 .2 \cdot 2 \cdot c i s 10^\circ. \] Putting the numbers together: \[ 1.1 \cdot 0.2 \cdot 2 = 0.44. \] Thus, our final result is: \[ 0.44 c i s 10^\circ. \]