9. The population growth of a certain city with a current population of 27,345 is modelled by the equation \( P=27,345\left(e^{0.005}\right) \), where \( P \) is the population of the city after \( t \) years and 0.005 is the rate of growth. (i) What will the population of the city be 10 years from now?

To find the population of the city 10 years from now, you can substitute \( t = 10 \) into the equation \( P = 27,345 \left(e^{0.005t}\right) \). This gives you \( P = 27,345 \left(e^{0.005 \cdot 10}\right) \). First, calculate \( 0.005 \cdot 10 = 0.05 \). Then, compute \( e^{0.05} \) which is approximately \( 1.0513 \). Now multiply: \( P \approx 27,345 \times 1.0513 \approx 28,799.86 \). Thus, the population of the city 10 years from now will be approximately **28,800**.