Question
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3.1 Given the arithmetic series:
3.1.1 Determine the number of terms in this series
3.1.2 Calculate the sum of this series
3.1.3 Calculate the sum of all the whole numbers up to and including 300 that are
NOT divisible by 6

Ask by Wells Powers. in South Africa
Mar 12,2025

Upstudy AI Solution

Tutor-Verified Answer

Answer

3.1.1 There are 48 terms in the series.
3.1.2 The sum of the series is 7,632.
3.1.3 The sum of all whole numbers up to and including 300 that are not divisible by 6 is 37,500.

Solution

3.1.1 Determine the number of terms in the series
The arithmetic series is
with first term , common difference , and last term .
We use the formula for the th term of an arithmetic sequence:
Plug in the values:
Subtract from both sides:
Divide both sides by :
Thus,
3.1.2 Calculate the sum of the series
The sum of an arithmetic series is given by:
Substitute , , and :
Simplify:
3.1.3 Calculate the sum of all whole numbers up to and including 300 that are NOT divisible by 6
  1. Sum of all whole numbers from 1 to 300:
    The sum of the first natural numbers is:
    For :
  2. Sum of all multiples of 6 up to 300:
    Multiples of 6 form an arithmetic series:
    Here, the first term is and the last term is . The number of terms is given by:
    The sum of this series is:
  3. Sum of numbers NOT divisible by 6:
    Subtract the sum of the multiples of 6 from the total sum:
Thus, the answers are:
  • 3.1.1 Number of terms:
  • 3.1.2 Sum of the series:
  • 3.1.3 Sum of whole numbers up to 300 not divisible by 6:

Answered by UpStudy AI and reviewed by a Professional Tutor

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Simplify this solution

Bonus Knowledge

First, let’s break down the series . This series has a common difference of (since ). The series can be expressed as . To find the number of terms, we set and solve for .
So,
Subtract from both sides:
Now, divide by :
Thus, there are terms in this arithmetic series.
To find the sum of this series, we can use the formula for the sum of an arithmetic series:
where is the number of terms, is the first term, and is the last term.
Substituting , , and :
So, the sum of the series is .
Now, for calculating the sum of all whole numbers up to and including that are NOT divisible by , we’ll first find the sum of all numbers up to and then subtract the sum of numbers divisible by .
The sum of numbers from to is given by:
Next, we find the number of integers up to that are divisible by :
The largest integer divisible by is , and the count is . The sum of integers divisible by from can be calculated as:
Finally, subtract the sum of numbers divisible by from the total sum:
Therefore, the sum of all whole numbers up to and including that are NOT divisible by is .

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