Factor completely. $$ 54 g^{2}-96 $$ $$ \square $$

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Factor the expression $$ 54g^2-96 $$.
Factor the expression by following steps:
- step0: Factor:
  $$54g^{2}-96$$
- step1: Factor the expression:
  $$6\left(9g^{2}-16\right)$$
- step2: Factor the expression:
  $$6\left(3g-4\right)\left(3g+4\right)$$
The factored form of $$54g^{2}-96$$ is $$6(3g-4)(3g+4)$$.
The expression $$54g^{2}-96$$ factors to $$6(3g-4)(3g+4)$$.

Factor completely.

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