If $$ x^{3}=-27 $$, then what is $$ x $$ ? $$ 0^{-9} $$ $$ 0^{-3} $$

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UpStudy AI · Accepted Answer

Solve the equation by following steps:
- step0: Solve for $$x$$:
  $$x^{3}=-27$$
- step1: Simplify the equation:
  $$\sqrt[3]{x^{3}}=\sqrt[3]{-27}$$
- step2: Calculate:
  $$x=\sqrt[3]{-27}$$
- step3: Simplify the root:
  $$x=-3$$
Let's solve the problem step by step.

1. **Finding $$ x $$ from the equation $$ x^{3} = -27 $$**:
   - To solve for $$ x $$, we take the cube root of both sides:
     $$
     x = \sqrt[3]{-27}
     $$
   - The cube root of $$-27$$ is $$-3$$. Therefore, we have:
     $$
     x = -3
     $$

2. **Calculating $$ 0^{-9} $$**:
   - The expression $$ 0^{-9} $$ represents $$ \frac{1}{0^{9}} $$. Since $$ 0^{9} = 0 $$, this results in division by zero, which is undefined.

3. **Calculating $$ 0^{-3} $$**:
   - Similarly, $$ 0^{-3} $$ represents $$ \frac{1}{0^{3}} $$. Again, since $$ 0^{3} = 0 $$, this also results in division by zero, which is undefined.

### Summary of Results:
- The value of $$ x $$ is $$ -3 $$.
- Both $$ 0^{-9} $$ and $$ 0^{-3} $$ are undefined due to division by zero.
$$ x = -3 $$.

If \( x^{3}=-27 \), then what is \( x \) ? \( 0^{-9} \) \( 0^{-3} \)

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