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A television programmer is arranging the order that seven movies will be seen between the hours of 6 P.M. and \( 8 \mathrm{~A} . \mathrm{M} \). Two of the movies have a G rating, and they are to be shown in the first two time blocks. One of the movies is rated NC-17, and it is to be shown in the last 0 of 1 of the time blocks, from 6 A.M. until 8 A.M. Given these restrictions, in how many ways can the seven movies be arranged during the indicated time blocks? The number of different ways the seven movies can be arranged during the indicated time blocks is \( \square \). (Type a whole number.)

Ask by Dickson Stewart. in the United States
Mar 18,2025

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Tutor-Verified Answer

Answer

There are 48 different ways to arrange the seven movies during the indicated time blocks.

Solution

Let the seven movies be arranged in 7 time blocks numbered 1 to 7. Two specific movies have a G rating and must be in time blocks 1 and 2, while one specific movie is rated NC-17 and must be in time block 7. 1. The two G-rated movies must occupy positions 1 and 2. They can be arranged in \[ 2! = 2 \text{ ways.} \] 2. The NC-17 movie is fixed in position 7, so there is only 1 possibility for that slot. 3. The remaining 4 movies (which are neither G-rated nor NC-17) can be arranged in the time blocks 3, 4, 5, and 6 in \[ 4! = 24 \text{ ways.} \] Multiplying these possibilities together, the total number of arrangements is \[ 2! \times 4! = 2 \times 24 = 48. \] Thus, the total number of ways to arrange the movies is \( 48 \).

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To solve the problem, we follow these steps: 1. **Positioning the G-rated Movies:** We need to show the 2 G-rated movies in the first two time blocks. There are \(2!\) (or 2) ways to arrange them in these two blocks. 2. **Positioning the NC-17 Movie:** We need to place the NC-17 movie in the last time block (the last 0 of 1). Since its position is fixed, there are \(1\) way to place it. 3. **Positioning the Remaining Movies:** There are 4 remaining movies (7 total - 2 G-rated - 1 NC-17 = 4 remaining). We need to arrange these 4 movies into the remaining 4 time blocks. This can be arranged in \(4!\) (or 24) different ways. 4. **Calculating Total Arrangements:** To find the total arrangements, we multiply the number of arrangements at each step: \[ \text{Total arrangements} = 2! \times 1 \times 4! = 2 \times 1 \times 24 = 48 \] So, the number of different ways the seven movies can be arranged during the indicated time blocks is \( \boxed{48} \).

Related Questions

1. On a single toss of one die, find the probability of obtaining a) The number 4 b) an odd number c) an even number d) a number less than 4 e) a number greater than 4 f) an odd or an even number 2. In a junior school class of 28 pupils, 7 are in both a sports team and the school band. There are 16 pupils involved in sports teams and 10 in the school band. Find the probability that a pupil chosen at random. a) is only in the school band b) is in either a sports team or the school band c) is in neither a sports team nor the school band 3. An integer is selected randomly from a set of integers \( \{1,2,3,4,5,6,7,8,9,10,11,12\} \). Find the probability that the integer is a) an even number or is divisible by 3 b) an even number and is not divisible by 3 c) not an even number and is not divisibleby 3 . 4. For the sample space \( S \), it is given that \[ \begin{array}{c} P(A)=0.5 \\ P(A \cup B)=0.6 \\ P(A \cap B)=0.2 \end{array} \] Find: a) \( P(B) \) b) \( P\left(A^{\prime} \cap B\right) \) c) \( P\left(A \cap B^{\prime}\right) \) d) \( P\left(A^{\prime} \cap B^{\prime}\right) \) 5. \( \quad C \) and \( D \) are two events where \( P(C)=0.1, P(D)=0.2 \) and \( P(C \cup D)=0.3 \). a) Determine whether \( C \) and \( D \) are two mutually exclusive events. b) Find \( P\left(C^{\prime}\right) \) and \( P\left(C^{\prime} \cap D^{\prime}\right) \) 6. The events \( A, B, C \) and \( D \) are mutually exclusive with \( P(A)=P(B)=0.3 \) and \( P(C)= \) \( P(D)=0.1 \). If \( E \) and \( F \) are events defined by \( E=A \cup D \) and \( F=B \cup C \), find a) \( P(E \cup F) \) b) \( P(E \cap F) \)
Probability Malaysia Mar 18, 2025

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