What is the total distance of the jumps of this length? \( \begin{array}{ll}\text { A } 12 \frac{1}{4} \text { feet } & \text { B } 16 \frac{1}{2} \text { feet } \\ \text { C } 17 \frac{5}{8} \text { feet } & \text { B } 18 \frac{1}{4} \text { feet }\end{array} \)

To find the total distance of the jumps, we first convert all the mixed numbers into improper fractions and then add them together. 1. Convert the jumps to improper fractions: - Jump A: \( 12 \frac{1}{4} = \frac{49}{4} \) - Jump B: \( 16 \frac{1}{2} = \frac{33}{2} = \frac{66}{4} \) - Jump C: \( 17 \frac{5}{8} = \frac{141}{8} \) - Jump D: \( 18 \frac{1}{4} = \frac{73}{4} \) 2. To add the distances, we need a common denominator. The least common multiple of 4 and 8 is 8: - Jump A: \( \frac{49}{4} = \frac{98}{8} \) - Jump B: \( \frac{66}{4} = \frac{132}{8} \) - Jump C: \( \frac{141}{8} \) - Jump D: \( \frac{73}{4} = \frac{146}{8} \) 3. Now add them together: \[ \frac{98}{8} + \frac{132}{8} + \frac{141}{8} + \frac{146}{8} = \frac{517}{8} \] 4. Convert \( \frac{517}{8} \) back to a mixed number: - \( 517 \div 8 = 64 \) remainder \( 5 \), so \( \frac{517}{8} = 64 \frac{5}{8} \) Thus, the total distance of the jumps is \( 64 \frac{5}{8} \) feet.