A line has a slope of 6 and passes through the point \( (-4,-20) \). Write its equation in slope- intercept form.

To find the equation of the line in slope-intercept form \(y = mx + b\), where \(m\) is the slope and \(b\) is the y-intercept, we can use the point \( (-4, -20) \) along with the slope \(m = 6\). We start by plugging the values into the equation: 1. Substitute the slope and the point into the equation: \(-20 = 6(-4) + b\). 2. Calculate \(6 \times -4 = -24\), so the equation becomes: \(-20 = -24 + b\). 3. Solving for \(b\), we add 24 to both sides: \(b = 4\). Now we have the slope and y-intercept: The equation of the line is \(y = 6x + 4\). To double-check your work, it's often helpful to substitute the x-value from your known point back into the final equation to ensure it produces the correct y-value. In this case, if you substitute \(x = -4\) into \(y = 6x + 4\), it should yield \(-20\), confirming your last step was correct!