Integrate the function \[ f(t)=\frac{t^{10}-\sqrt{t}}{t^{3}} \]
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The Deep Dive
To integrate the function \[ f(t) = \frac{t^{10} - \sqrt{t}}{t^3}, \] we first simplify the expression. We can rewrite \( \sqrt{t} \) as \( t^{1/2} \): \[ f(t) = \frac{t^{10}}{t^3} - \frac{\sqrt{t}}{t^3} = t^{10 - 3} - t^{1/2 - 3} = t^{7} - t^{-5/2}. \] Now, we can integrate \( f(t) \): \[ \int f(t) \, dt = \int (t^{7} - t^{-5/2}) \, dt. \] Let's integrate each term separately: 1. For \( t^7 \): \[ \int t^{7} \, dt = \frac{t^{7 + 1}}{7 + 1} = \frac{t^{8}}{8}. \] 2. For \( -t^{-5/2} \): \[ \int -t^{-5/2} \, dt = -\frac{t^{-5/2 + 1}}{-5/2 + 1} = -\frac{t^{-3/2}}{-3/2} = \frac{2}{3} t^{-3/2}. \] Now, we can combine these results: \[ \int f(t) \, dt = \frac{t^{8}}{8} + \frac{2}{3} t^{-3/2} + C, \] where \( C \) is the constant of integration. Thus, the final answer is: \[ \int f(t) \, dt = \frac{t^{8}}{8} + \frac{2}{3} t^{-3/2} + C. \]