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Integrate the function \[ f(t)=\frac{t^{10}-\sqrt{t}}{t^{3}} \]

Ask by Vega Haynes. in South Africa
Mar 01,2025

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Answer

The integral of \( f(t) = \frac{t^{10} - \sqrt{t}}{t^{3}} \) is \( \frac{t^8}{8} + \frac{2}{3} t^{-\frac{3}{2}} + C \), where \( C \) is the constant of integration.

Solution

We want to integrate   ∫ [(t¹⁰ - √t) / t³] dt. Step 1. Simplify the integrand. Write the function as follows:   (t¹⁰ - √t) / t³ = t¹⁰/t³ - √t/t³. Recall that t¹⁰/t³ = t^(10 - 3) = t⁷. Also, express √t as t^(1/2); thus   √t/t³ = t^(1/2)/t³ = t^(1/2 - 3) = t^(-5/2). So the integrand becomes:   t⁷ - t^(-5/2). Step 2. Integrate term by term. The integral now is:   ∫ t⁷ dt - ∫ t^(-5/2) dt. For the first term:   ∫ t⁷ dt = t^(7+1)/(7+1) = t⁸/8. For the second term, remember the power rule for integration:   ∫ t^p dt = t^(p+1)/(p+1), provided p ≠ -1. Here, p = -5/2 so that   ∫ t^(-5/2) dt = t^((-5/2)+1)/((-5/2)+1)            = t^(-3/2)/(-3/2) = - (2/3) t^(-3/2). Now, because the term in the original integrand is -t^(-5/2), its integral becomes:   - ∫ t^(-5/2) dt = - [ - (2/3) t^(-3/2) ] = (2/3) t^(-3/2). Step 3. Combine the results. Thus, the integrated function is:   (t⁸/8) + (2/3) t^(-3/2) + C, where C is the constant of integration. Final Answer:   ∫ [(t¹⁰ - √t)/t³] dt = t⁸/8 + (2/3) t^(-3/2) + C.

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The Deep Dive

To integrate the function \[ f(t) = \frac{t^{10} - \sqrt{t}}{t^3}, \] we first simplify the expression. We can rewrite \( \sqrt{t} \) as \( t^{1/2} \): \[ f(t) = \frac{t^{10}}{t^3} - \frac{\sqrt{t}}{t^3} = t^{10 - 3} - t^{1/2 - 3} = t^{7} - t^{-5/2}. \] Now, we can integrate \( f(t) \): \[ \int f(t) \, dt = \int (t^{7} - t^{-5/2}) \, dt. \] Let's integrate each term separately: 1. For \( t^7 \): \[ \int t^{7} \, dt = \frac{t^{7 + 1}}{7 + 1} = \frac{t^{8}}{8}. \] 2. For \( -t^{-5/2} \): \[ \int -t^{-5/2} \, dt = -\frac{t^{-5/2 + 1}}{-5/2 + 1} = -\frac{t^{-3/2}}{-3/2} = \frac{2}{3} t^{-3/2}. \] Now, we can combine these results: \[ \int f(t) \, dt = \frac{t^{8}}{8} + \frac{2}{3} t^{-3/2} + C, \] where \( C \) is the constant of integration. Thus, the final answer is: \[ \int f(t) \, dt = \frac{t^{8}}{8} + \frac{2}{3} t^{-3/2} + C. \]

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