Question
upstudy study bank question image url

\( -40>25-5 x \) and \( 2 x+4 \leq 29- \)

Ask by Harper Mitchell. in the United States
Feb 26,2025

Upstudy AI Solution

Tutor-Verified Answer

Answer

The solution to the first inequality is \( x > 13 \).

Solution

It looks like there are two inequalities in your message. The first one is   –40 > 25 – 5x. The second inequality, however, appears to be incomplete—it ends with “29–” and is missing the term or expression that should come after the minus sign. Could you please check and provide the complete form of the second inequality so I can help solve it? In the meantime, here’s the step‑by‑step solution for the first inequality: Step 1. Write the inequality:   –40 > 25 – 5x Step 2. Subtract 25 from both sides to isolate the term with x:   –40 – 25 > 25 – 5x – 25   –65 > –5x Step 3. Divide both sides by –5. Remember that dividing by a negative number reverses the inequality sign:   (–65)/(–5) < x    (inequality sign flips)   13 < x Which can be rewritten as:   x > 13 So, the solution for the first inequality is all real numbers x such that x > 13. Once you provide the complete form of the second inequality, I can help solve that as well.

Answered by UpStudy AI and reviewed by a Professional Tutor

error msg
Explain
Simplify this solution

Beyond the Answer

To solve the first inequality \( -40 > 25 - 5x \), you can start by isolating \( x \). Subtract 25 from both sides to get \( -65 > -5x \). Dividing both sides by -5 (remember to flip the inequality sign when dividing by a negative number), gives \( x > 13 \). For the second inequality \( 2x + 4 \leq 29 \), begin by subtracting 4 from both sides, resulting in \( 2x \leq 25 \). Dividing both sides by 2 yields \( x \leq 12.5 \). Therefore, when combining these results, the solution indicates that there are no values for \( x \) that satisfy both inequalities, as \( x \) cannot be both greater than 13 and less than or equal to 12.5. Remember, always carefully check your work and the operations applied to inequalities, especially regarding direction changes when multiplying or dividing by negative numbers!

Related Questions

ISCELÁNEA cribir, por simple inspección, el resultado de: \( \begin{array}{lll}(x+2)^{2} & \text { 14. }(x+y+1)(x-y-1) & \text { 27. }\left(2 a^{3}-5 b^{4}\right)^{2} \\ (x+2)(x+3) & \text { 15. }(1-a)(a+1) & \text { 28. }\left(a^{3}+12\right)\left(a^{3}-15\right) \\ (x+1)(x-1) & \text { 16. }(m-8)(m+12) & \text { 29. }\left(m^{2}-m+n\right)\left(n+m+m^{2}\right) \\ (x-1)^{2} & \text { 17. }\left(x^{2}-1\right)\left(x^{2}+3\right) & \text { 30. }\left(x^{4}+7\right)\left(x^{4}-11\right) \\ (n+3)(n+5) & \text { 18. }\left(x^{3}+6\right)\left(x^{3}-8\right) & \text { 31. }(11-a b)^{2} \\ (m-3)(m+3) & \text { 19. }\left(5 x^{3}+6 m^{4}\right)^{2} & \text { 32. }\left(x^{2} y^{3}-8\right)\left(x^{2} y^{3}+6\right) \\ (a+b-1)(a+b+1) & \text { 20. }\left(x^{4}-2\right)\left(x^{4}+5\right) & \text { 33. }(a+b)(a-b)\left(a^{2}-b^{2}\right) \\ (1+b)^{3} & \text { 21. }(1-a+b)(b-a-1) & \text { 34. }(x+1)(x-1)\left(x^{2}-2\right) \\ \left(a^{2}+4\right)\left(a^{2}-4\right) & \text { 22. }\left(a^{x}+b^{n}\right)\left(a^{x}-b^{n}\right) & \text { 35. }(a+3)\left(a^{2}+9\right)(a-3) \\ \left(3 a b-5 x^{2}\right)^{2} & \text { 23. }\left(x^{a+1}-8\right)\left(x^{a+1}+9\right) & \text { 36. }(x+5)(x-5)\left(x^{2}+1\right) \\ (a b+3)(3-a b) & \text { 24. }\left(a^{2} b^{2}+c^{2}\right)\left(a^{2} b^{2}-c^{2}\right) & \text { 37. }(a+1)(a-1)(a+2)(a-2) \\ (1-4 a x)^{2} & \text { 25. }(2 a+x)^{3} & \text { 36. }\left(x^{2}-11\right)\left(x^{2}-2\right)\end{array} \) \( \left(a^{2}+8\right)\left(a^{2}-7\right) \)
Algebra Mexico Feb 26, 2025
Try Premium now!
Try Premium and ask Thoth AI unlimited math questions now!
Maybe later Go Premium
Study can be a real struggle
Why not UpStudy it?
Select your plan below
Premium

You can enjoy

Start now
  • Step-by-step explanations
  • 24/7 expert live tutors
  • Unlimited number of questions
  • No interruptions
  • Full access to Answer and Solution
  • Full Access to PDF Chat, UpStudy Chat, Browsing Chat
Basic

Totally free but limited

  • Limited Solution
Welcome to UpStudy!
Please sign in to continue the Thoth AI Chat journey
Continue with Email
Or continue with
By clicking “Sign in”, you agree to our Terms of Use & Privacy Policy