If an object starts moving at \( t_{0}=4 \mathrm{~s} \) and stops moving at \( t_{1}=9 \mathrm{~s} \), then the \( \Delta t=t_{1}-t_{0}= \) 5 s 1s 6 s 9 s 2 s

The time interval \( \Delta t \) is calculated by subtracting the starting time \( t_{0} \) from the stopping time \( t_{1} \). So, \( \Delta t = t_{1} - t_{0} = 9 \mathrm{~s} - 4 \mathrm{~s} = 5 \mathrm{~s} \). Therefore, the correct answer is 5 s. Just like calculating intervals in physics, time management in daily life can help maximize productivity! For instance, if you allocate a specific block of time for focused work, you can often accomplish tasks more effectively than if you allow distractions to lengthen your task time. Have you ever made a common mistake while measuring time intervals, like forgetting to include all relevant parts of the problem? It’s easy to overlook the units or to confuse the starting and stopping times! To avoid this, always double-check your calculations and make a note of your figures, because a small mistake can lead to a big miscalculation!