(a) $$ f(x)=2400=2 x $$ (b) $$ A(x)=2400 x-2 x^{2} $$ (d) Finst write the expression for the derivetive used to find the $$ x $$ value that maximizes area $$ \frac{d A}{d x}=-4 x+2400 $$ The $$ x $$-value leading to the maximum area is $$ \square \square
abla $$

Question

(a) $$ f(x)=2400=2 x $$ (b) $$ A(x)=2400 x-2 x^{2} $$ (d) Finst write the expression for the derivetive used to find the $$ x $$ value that maximizes area $$ \frac{d A}{d x}=-4 x+2400 $$ The $$ x $$-value leading to the maximum area is $$ \square \square 
abla $$

UpStudy AI · Accepted Answer

To find the $$ x $$-value that maximizes the area given the function $$ A(x) = 2400x - 2x^2 $$, we start with the derivative you provided:

$$
\frac{dA}{dx} = -4x + 2400
$$

To find the critical points, we set the derivative equal to zero:

$$
-4x + 2400 = 0
$$

Now, solve for $$ x $$:

$$
4x = 2400
$$
$$
x = \frac{2400}{4} = 600
$$

Thus, the $$ x $$-value that maximizes the area is $$ 600 $$.

So, the final answer is:

The $$ x $$-value leading to the maximum area is $$ 600 $$.
The $$ x $$-value that maximizes the area is $$ 600 $$.

(a) \( f(x)=2400=2 x \) (b) \( A(x)=2400 x-2 x^{2} \) (d) Finst write the expression for the derivetive used to find the \( x \) value that maximizes area \( \frac{d A}{d x}=-4 x+2400 \) The \( x \)-value leading to the maximum area is \( \square \square \nabla \)

Upstudy AI Solution

Answer

Solution

Mind Expander

Related Questions

Latest Calculus Questions