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SUBMIT ANSWER [-19 Points] DETAILS MY NOTES CURRENMEDMATH11 13.2.006.EP. ASK YOUR TEACHER PRACTICE ANOTHER Consider the following. A dossge of 75 mg is ordered, and the drug available is labeled 0.1 g in 1.5 mL . Complete the following statement. The available dosage strength is 0.1 g in 1.5 mL . The goal is to determine how many mL will be needed to prepare a dosage of 75 mg. The units are \( \square \) Gifferent so a conversion ratio will not be used e. Set up an equation that can be used to calculate the dosage using DA. Calculate the dosage using DA . Express your mL answer to the nearest tenth. \( \qquad \) mL ebook SUBMIT ANSWER

Ask by Hodgson Lynch. in the United States
Mar 20,2025

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To prepare a 75 mg dosage, you need **1.1 mL** of the drug.

Solution

**Step 1. Convert the Ordered Dosage to the Same Unit** The ordered dosage is 75 mg. Since the available drug is given in grams, convert 75 mg to grams. \[ 75\, \text{mg} \times \frac{1 \, \text{g}}{1000 \, \text{mg}} = 0.075\, \text{g} \] **Step 2. Set Up the Proportion (DA Equation)** The concentration of the drug is given as 0.1 g in 1.5 mL. This gives the ratio: \[ \frac{0.1\, \text{g}}{1.5\, \text{mL}} \] We need to find \( x \) mL corresponding to 0.075 g. Set up the proportion: \[ \frac{0.1\, \text{g}}{1.5\, \text{mL}} = \frac{0.075\, \text{g}}{x\, \text{mL}} \] **Step 3. Solve for \( x \)** Cross-multiply to solve the equation: \[ 0.1 \cdot x = 1.5 \cdot 0.075 \] Calculate the right-hand side: \[ 1.5 \times 0.075 = 0.1125 \] So, \[ 0.1x = 0.1125 \] Now, solve for \( x \): \[ x = \frac{0.1125}{0.1} = 1.125\, \text{mL} \] **Step 4. Round to the Nearest Tenth** Rounded to the nearest tenth, the volume required is: \[ 1.1\, \text{mL} \]

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To convert the ordered dosage of 75 mg to grams, note that 1 g = 1000 mg, so 75 mg is equal to 0.075 g. The available medication is labeled as 0.1 g in 1.5 mL. To set up an equation using the desired amount (DA), we can use the proportion: \[ \frac{0.1 \text{ g}}{1.5 \text{ mL}} = \frac{0.075 \text{ g}}{x \text{ mL}} \] Cross-multiplying gives us: \[ 0.1x = 0.075 \cdot 1.5 \] Now we calculate \(0.075 \cdot 1.5\): \[ 0.075 \cdot 1.5 = 0.1125 \] Then, dividing both sides by 0.1 gives: \[ x = \frac{0.1125}{0.1} = 1.125 \text{ mL} \] Rounding to the nearest tenth, we find: \[ x \approx 1.1 \text{ mL} \] So, the answer is \(1.1\) mL.

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