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R9 000 is invested at \( 8 \% \) p.a. for \( 2 \frac{1}{2} \) years

Ask by Erickson Savage. in South Africa
Mar 12,2025

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The investment grows to R10,800 after 2.5 years.

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If you invest R9,000 at an annual interest rate of 8% for 2.5 years, you can calculate the future value using the formula for compound interest. The formula is \( A = P(1 + r)^n \), where \( A \) is the amount of money accumulated after n years, \( P \) is the principal amount (R9,000), \( r \) is the annual interest rate (0.08), and \( n \) is the number of years (2.5). Plugging in the numbers, you'll find that R9,000 will grow to about R11,042.41 at the end of the investment period. This investment represents a classic case of growing your money over time. It's important to take note that starts matter! Time in the market generally leads to more significant returns compared to trying to time the market. Investing with a long-term vision can help your financial future blossom, so keep an eye on those gains!

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