Answer
### 15. Kinetic Energy Problem
**Question:**
A car with a mass of \(1200\,\text{kg}\) is moving at \(20\,\text{m/s}\). What is its kinetic energy?
**Solution:**
Kinetic energy = \(\frac{1}{2} \times 1200 \times 20^2 = 240,000\,\text{Joules}\).
---
### 16. Potential Energy Problem
**Question:**
A rock of mass \(3\,\text{kg}\) is lifted to a height of \(15\,\text{m}\). What is its gravitational potential energy?
**Solution:**
Gravitational potential energy = \(3 \times 9.8 \times 15 = 441\,\text{Joules}\).
Solution
### 15. Kinetic Energy Problem
**Question:**
A car with a mass of \(1200\,\text{kg}\) is moving at a speed of \(20\,\text{m/s}\). Calculate its kinetic energy.
**Solution:**
1. The formula for kinetic energy is
\[
KE = \frac{1}{2}mv^2
\]
2. Substitute the given values into the formula:
\[
KE = \frac{1}{2} \times 1200 \times (20)^2
\]
3. Calculate the square of the speed:
\[
(20)^2 = 400
\]
4. Multiply the values:
\[
KE = \frac{1}{2} \times 1200 \times 400
\]
First calculate \(\frac{1}{2} \times 1200 = 600\), then
\[
KE = 600 \times 400 = 240000\,\text{Joules}
\]
---
### 16. Potential Energy Problem
**Question:**
A rock of mass \(3\,\text{kg}\) is lifted to a height of \(15\,\text{m}\) above the ground. Calculate its gravitational potential energy. Assume the acceleration due to gravity is \(9.8\,\text{m/s}^2\).
**Solution:**
1. The formula for gravitational potential energy is
\[
U = mgh
\]
2. Substitute the known values:
\[
U = 3 \times 9.8 \times 15
\]
3. First, calculate the product of the mass and gravitational acceleration:
\[
3 \times 9.8 = 29.4
\]
4. Then, multiply by the height:
\[
U = 29.4 \times 15 = 441\,\text{Joules}
\]
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