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1. (extra credit 10 pts.) Consider the function of two variables given by \( f(x, y)=\frac{1}{2}(x+y+|x-y|) \) Experiment with \( f \) on scratch paper for various real-number inputs in plac \( x \) and \( y \). Show two of the calculations below and briefly explain what this function does.

Ask by Sullivan Frank. in the United States
Mar 13,2025

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When \( x = 3 \) and \( y = 1 \), \( f(3, 1) = 3 \). When \( x = 1 \) and \( y = 4 \), \( f(1, 4) = 4 \). The function calculates the average of \( x \) and \( y \), adjusting based on their difference.

Solution

To analyze the function \( f(x, y) = \frac{1}{2}(x + y + |x - y|) \), we will evaluate it for two different pairs of real-number inputs. ### Step 1: Understanding the Function The function consists of three parts: 1. \( x \) 2. \( y \) 3. \( |x - y| \) (the absolute difference between \( x \) and \( y \)) The absolute value \( |x - y| \) will affect the output based on the relationship between \( x \) and \( y \). ### Step 2: Evaluating the Function #### Example 1: \( x = 3, y = 1 \) 1. Calculate \( |x - y| \): \[ |3 - 1| = |2| = 2 \] 2. Substitute into the function: \[ f(3, 1) = \frac{1}{2}(3 + 1 + 2) = \frac{1}{2}(6) = 3 \] #### Example 2: \( x = 1, y = 4 \) 1. Calculate \( |x - y| \): \[ |1 - 4| = |-3| = 3 \] 2. Substitute into the function: \[ f(1, 4) = \frac{1}{2}(1 + 4 + 3) = \frac{1}{2}(8) = 4 \] ### Step 3: Explanation of the Function The function \( f(x, y) \) effectively computes the average of \( x \) and \( y \) while adjusting for the distance between them. - When \( x \) is greater than \( y \), \( |x - y| \) adds to the sum, resulting in a value that is influenced more by the larger number. - Conversely, when \( y \) is greater than \( x \), the same effect occurs, but the function still averages the two values. In essence, this function can be interpreted as a way to find a "weighted average" of \( x \) and \( y \) that takes into account their difference, ensuring that the output is always at least as large as the larger of the two inputs. ### Summary of Results - For \( (3, 1) \), \( f(3, 1) = 3 \) - For \( (1, 4) \), \( f(1, 4) = 4 \) This function is useful in scenarios where the relationship between two variables is important, and it provides a way to balance their contributions based on their relative sizes.

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First, let's take \( x = 3 \) and \( y = 1 \). Substituting these values into the function: \[ f(3, 1) = \frac{1}{2}(3 + 1 + |3 - 1|) = \frac{1}{2}(3 + 1 + 2) = \frac{1}{2}(6) = 3. \] Now, for \( x = 2 \) and \( y = 5 \): \[ f(2, 5) = \frac{1}{2}(2 + 5 + |2 - 5|) = \frac{1}{2}(2 + 5 + 3) = \frac{1}{2}(10) = 5. \] This function effectively finds the average of \( x \) and \( y \), adjusted by the absolute difference between them. It can be interpreted as giving the larger of the two numbers or averaging them based on their relative values, which is why we see results that lean toward the higher input when one value is significantly greater than the other.

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