25. \( \frac{1-\frac{2-\frac{1}{x}}{x}}{1-\frac{1}{x}} \)

Calculate or simplify the expression \( (1-\frac{2-\frac{1}{x}}{x})/(1-\frac{1}{x}) \). Simplify the expression by following steps: - step0: Solution: \(\frac{\left(1-\frac{2-\frac{1}{x}}{x}\right)}{\left(1-\frac{1}{x}\right)}\) - step1: Remove the parentheses: \(\frac{1-\frac{2-\frac{1}{x}}{x}}{1-\frac{1}{x}}\) - step2: Subtract the terms: \(\frac{1-\frac{\frac{2x-1}{x}}{x}}{1-\frac{1}{x}}\) - step3: Divide the terms: \(\frac{1-\frac{2x-1}{x^{2}}}{1-\frac{1}{x}}\) - step4: Subtract the terms: \(\frac{\frac{x^{2}-2x+1}{x^{2}}}{1-\frac{1}{x}}\) - step5: Subtract the terms: \(\frac{\frac{x^{2}-2x+1}{x^{2}}}{\frac{x-1}{x}}\) - step6: Multiply by the reciprocal: \(\frac{x^{2}-2x+1}{x^{2}}\times \frac{x}{x-1}\) - step7: Rewrite the expression: \(\frac{\left(x-1\right)^{2}}{x^{2}}\times \frac{x}{x-1}\) - step8: Reduce the fraction: \(\frac{x-1}{x}\) The simplified form of the given expression \( \frac{1-\frac{2-\frac{1}{x}}{x}}{1-\frac{1}{x}} \) is \( \frac{x-1}{x} \).