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You are dealt one card from a 62 -card deck, Find the probability that you are not deall a card with number from 2 to 7 . The probability is \( \square \). (Type an integer or a simplified fraction.)

Ask by Mejia Ayala. in the United States
Mar 09,2025

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Answer

The probability is \( \frac{19}{31} \).

Solution

1. The total number of cards in the deck is \(62\). 2. There are 6 numbers from 2 to 7. Assuming each number appears once per suit (usually 4 suits), the total number of cards with a number from 2 to 7 is \[ 6 \times 4 = 24. \] 3. The number of cards that are not numbered 2 to 7 is \[ 62 - 24 = 38. \] 4. Therefore, the probability of being dealt a card that is not numbered from 2 to 7 is \[ \frac{38}{62}. \] 5. Simplify the fraction by dividing the numerator and denominator by 2: \[ \frac{38 \div 2}{62 \div 2} = \frac{19}{31}. \] The probability is \( \frac{19}{31} \).

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To find the probability of not being dealt a card numbered from 2 to 7 in a 62-card deck, let's first identify how many cards fall within that range. The numbers 2 to 7 include 2, 3, 4, 5, 6, and 7, which accounts for a total of 6 cards. With a 62-card deck, the total number of cards not numbered from 2 to 7 is \(62 - 6 = 56\). Now, the probability of being dealt a card not in that range is calculated by dividing the number of favorable outcomes (non-2 to 7 cards) by the total number of outcomes (total cards in the deck): \[ P(\text{not 2 to 7}) = \frac{56}{62} = \frac{28}{31} \] Thus, the probability is \(\frac{28}{31}\).

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