In the chemical equation: \( \mathrm{CaCO}_{3}(\mathrm{~s}) \rightarrow \mathrm{CaO}(\mathrm{s})+\mathrm{CO}_{2}(\mathrm{~g}) \) Which statement is true about the conservation of matter? A. The number of calcium atoms is different in the reactants and products B. The number of carbon atoms is different in the reactants and products C. The number of oxygen atoms is the same in the reactants and products D. The total mass of reactants is less than the total mass of products
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In a chemical reaction, the law of conservation of matter states that matter cannot be created or destroyed. Thus, the number of each type of atom must remain constant between reactants and products. In the given equation, both sides contain the same number of calcium, carbon, and oxygen atoms. The correct statement regarding the conservation of matter is C. The number of oxygen atoms is the same in the reactants and products. There are three oxygen atoms in \( \mathrm{CaCO}_{3} \) and also three present when it breaks down into \( \mathrm{CaO} \) (one) and \( \mathrm{CO}_{2} \) (two). Now, let's dive into a little background fun: Did you know that the thermal decomposition of calcium carbonate (like the one found in limestone) was used by ancient builders? They would heat it to create lime (calcium oxide), which became essential for making mortar and plaster in constructions that still stand today! And a little real-world application to ponder: This reaction is crucial in industries for producing lime for construction and in treatments for waste and water purification, making it a key player in both environmental and urban architecture spaces!
