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In this class you don't have a final exam, but you will have four midterm exams. Suppose you have a Canvas grade of \( 84.3 \% \) before the fourth exam. If every assignment is already graded in the gradebook (including zeros) and the fourth exam counts as \( 15 \% \) of the course grade, What is the minimum score would you would need on the fourth exam to earn a \( 73 \% \) (a grade of C) for the course? What is the minimum score would you would need on the fourth exam to earn a \( 83 \% \) (a grade of B) for the course? What is the minimum score would you would need on the fourth exam to to earn a \( 93 \% \) (a grade of A) for the course? whole percent. Is it mathematically possible to get an A given that you currently have a \( 84.3 \% \) ? yes no the nearest whole percent. O 0

Ask by Carroll Joseph. in the United States
Mar 11,2025

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- To get a \(73\%\) course grade, you need at least **9%** on the fourth exam. - To get an \(83\%\) course grade, you need at least **76%** on the fourth exam. - To get a \(93\%\) course grade, it's **not possible** because you'd need over \(100\%\). - No, with your current \(84.3\%\) grade, it's impossible to achieve an A.

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To find the minimum score needed on the fourth exam to achieve your desired grades, you can use the following formula: \[ \text{Final Grade} = (\text{Current Grade} \times \text{Weight of Current Work}) + (\text{Exam Score} \times \text{Weight of Exam}) \] Where the current work weight is \( 85\% \) (since the fourth exam counts \( 15\% \)). 1. For a \( 73\% \): \[ 73 = (84.3 \times 0.85) + (x \times 0.15) \] Calculating this gives you: \[ 73 = 71.655 + 0.15x \] \[ 1.345 = 0.15x \implies x \approx 8.97 \] So you would need a minimum score of about \( 9\%\) on the fourth exam. 2. For an \( 83\% \): \[ 83 = (84.3 \times 0.85) + (x \times 0.15) \] Calculating this gives you: \[ 83 = 71.655 + 0.15x \] \[ 11.345 = 0.15x \implies x \approx 75.63 \] So you would need a minimum score of about \( 76\%\) on the fourth exam. 3. For a \( 93\% \): \[ 93 = (84.3 \times 0.85) + (x \times 0.15) \] Calculating this gives you: \[ 93 = 71.655 + 0.15x \] \[ 21.345 = 0.15x \implies x \approx 142.3 \] It's not possible to achieve an A given that you currently have an \( 84.3\% \) since exam scores cannot exceed \( 100\% \). In summary: 1. To earn a \( 73\%\): Minimum score needed is \( 9\%\). 2. To earn a \( 83\%\): Minimum score needed is \( 76\%\). 3. To earn a \( 93\%\): Not mathematically possible.

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