In this class you don't have a final exam, but you will have four midterm exams. Suppose you have a Canvas grade of $$ 84.3 \% $$ before the fourth exam. If every assignment is already graded in the gradebook (including zeros) and the fourth exam counts as $$ 15 \% $$ of the course grade, What is the minimum score would you would need on the fourth exam to earn a $$ 73 \% $$ (a grade of C) for the course? What is the minimum score would you would need on the fourth exam to earn a $$ 83 \% $$ (a grade of B) for the course? What is the minimum score would you would need on the fourth exam to to earn a $$ 93 \% $$ (a grade of A) for the course? whole percent. Is it mathematically possible to get an A given that you currently have a $$ 84.3 \% $$ ? yes no the nearest whole percent. O 0

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UpStudy AI · Accepted Answer

1. Let $$ x $$ be the score on the fourth exam (in percent).

2. The overall course grade is calculated by weighting the current grade and the exam score:
   $$
   0.85 \times 84.3 + 0.15 \times x.
   $$

3. **For a $$73\%$$ course grade:**
   
   Set up the equation:
   $$
   0.85 \times 84.3 + 0.15 \times x = 73.
   $$
   First, compute:
   $$
   0.85 \times 84.3 = 71.655.
   $$
   Then,
   $$
   71.655 + 0.15x = 73.
   $$
   Isolate $$ x $$:
   $$
   0.15x = 73 - 71.655 = 1.345,
   $$
   $$
   x = \frac{1.345}{0.15} \approx 8.97.
   $$
   Rounded to the nearest whole percent:
   $$
   x \approx 9\%.
   $$

4. **For an $$83\%$$ course grade:**
   
   Set up the equation:
   $$
   0.85 \times 84.3 + 0.15 \times x = 83.
   $$
   Using the previous value:
   $$
   71.655 + 0.15x = 83,
   $$
   $$
   0.15x = 83 - 71.655 = 11.345,
   $$
   $$
   x = \frac{11.345}{0.15} \approx 75.63.
   $$
   Rounded to the nearest whole percent:
   $$
   x \approx 76\%.
   $$

5. **For a $$93\%$$ course grade:**
   
   Set up the equation:
   $$
   0.85 \times 84.3 + 0.15 \times x = 93.
   $$
   Compute:
   $$
   71.655 + 0.15x = 93,
   $$
   $$
   0.15x = 93 - 71.655 = 21.345,
   $$
   $$
   x = \frac{21.345}{0.15} \approx 142.3.
   $$
   Rounded to the nearest whole percent:
   $$
   x \approx 143\%.
   $$
   Since an exam score cannot exceed $$100\%$$, it is mathematically impossible to achieve this.

6. **Is it mathematically possible to get an A given your current $$84.3\%$$ on Canvas?**

No, because you would need to score approximately $$143\%$$ on the fourth exam, which is impossible.

**Final Answers:**
- Minimum score for a $$73\%$$ course grade: **$$9\%$$**
- Minimum score for an $$83\%$$ course grade: **$$76\%$$**
- Minimum score for a $$93\%$$ course grade: **Not possible (requires $$143\%$$)**
- It is mathematically impossible to get an A with a current grade of $$84.3\%$$.
- To get a $$73\%$$ course grade, you need at least **9%** on the fourth exam. - To get an $$83\%$$ course grade, you need at least **76%** on the fourth exam. - To get a $$93\%$$ course grade, it's **not possible** because you'd need over $$100\%$$. - No, with your current $$84.3\%$$ grade, it's impossible to achieve an A.

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