1)) Factor $$ x^{4}-8 x^{2}+16 $$ completely. All factors in your answer should have integer coefficients.

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Factor the expression $$ x^4-8x^2+16 $$.
Factor the expression by following steps:
- step0: Factor:
  $$x^{4}-8x^{2}+16$$
- step1: Calculate:
  $$x^{4}+4x^{3}+4x^{2}-4x^{3}-16x^{2}-16x+4x^{2}+16x+16$$
- step2: Rewrite the expression:
  $$x^{2}	imes x^{2}+x^{2}	imes 4x+x^{2}	imes 4-4x	imes x^{2}-4x	imes 4x-4x	imes 4+4x^{2}+4	imes 4x+4	imes 4$$
- step3: Factor the expression:
  $$x^{2}\left(x^{2}+4x+4ight)-4x\left(x^{2}+4x+4ight)+4\left(x^{2}+4x+4ight)$$
- step4: Factor the expression:
  $$\left(x^{2}-4x+4ight)\left(x^{2}+4x+4ight)$$
- step5: Factor the expression:
  $$\left(x-2ight)^{2}\left(x^{2}+4x+4ight)$$
- step6: Factor the expression:
  $$\left(x-2ight)^{2}\left(x+2ight)^{2}$$
The complete factorization of $$x^{4}-8x^{2}+16$$ is $$(x-2)^{2}(x+2)^{2}$$.
$$ x^{4}-8x^{2}+16 = (x-2)^{2}(x+2)^{2} $$

1)) Factor completely.
All factors in your answer should have integer coefficients.

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1)) Factor completely. All factors in your answer should have integer coefficients.