Question
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Solve for \( y \). \[ y^{2}-y-2=0 \] If there is more than one solution, separate them with commas. If there is no solution, click on "No solution." \( y=\square \)

Ask by Kirk Harper. in the United States
Mar 10,2025

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Tutor-Verified Answer

Answer

\( y = 2, -1 \)

Solution

1. Start with the quadratic equation: \[ y^2 - y - 2 = 0 \] 2. Factor the quadratic by finding two numbers that multiply to \(-2\) and add to \(-1\). The numbers \(-2\) and \(1\) satisfy these conditions: \[ y^2 - y - 2 = (y - 2)(y + 1) \] 3. Set each factor equal to zero and solve for \( y \): \[ y - 2 = 0 \quad \text{or} \quad y + 1 = 0 \] \[ y = 2 \quad \text{or} \quad y = -1 \] 4. The solutions are: \[ y = 2, -1 \]

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To solve the equation \( y^{2}-y-2=0 \), we can factor it. We need two numbers that multiply to \(-2\) and add to \(-1\). These numbers are \(-2\) and \(1\). Thus, we can factor the equation as: \[ (y-2)(y+1)=0 \] Setting each factor to zero gives us the solutions: \[ y-2=0 \quad \Rightarrow \quad y=2 \] \[ y+1=0 \quad \Rightarrow \quad y=-1 \] So, the solutions are: \( y=2, -1 \)

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