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5.4 Calculate the final amount if R3200 is invested for 5 years at \( 7.25 \% \) p.a compound interest. Round off the answer to 2 decirnal places.

Ask by Floyd Gibbs. in South Africa
Feb 25,2025

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Tutor-Verified Answer

Answer

The final amount after investing R3200 for 5 years at 7.25% compound interest is R4540.84.

Solution

To calculate the final amount after investing R3200 for 5 years at a compound interest rate of 7.25% per annum, we can use the formula for compound interest: \[ A = P \times (1 + \frac{r}{100})^n \] Where: - \( A \) is the final amount - \( P \) is the principal amount (initial investment) = R3200 - \( r \) is the annual interest rate = 7.25% - \( n \) is the number of years = 5 Substitute the given values into the formula: \[ A = 3200 \times (1 + \frac{7.25}{100})^5 \] Now, we can calculate the final amount using the formula. Calculate the value by following steps: - step0: Calculate: \(3200\left(1+\frac{7.25}{100}\right)^{5}\) - step1: Divide the terms: \(3200\left(1+\frac{29}{400}\right)^{5}\) - step2: Add the numbers: \(3200\left(\frac{429}{400}\right)^{5}\) - step3: Simplify: \(3200\times \frac{429^{5}}{400^{5}}\) - step4: Rewrite the expression: \(400\times 8\times \frac{429^{5}}{400^{5}}\) - step5: Reduce the numbers: \(8\times \frac{429^{5}}{400^{4}}\) - step6: Rewrite the expression: \(8\times \frac{429^{5}}{16^{4}\times 25^{4}}\) - step7: Rewrite the expression: \(2^{3}\times \frac{429^{5}}{2^{16}\times 25^{4}}\) - step8: Reduce the numbers: \(1\times \frac{429^{5}}{2^{13}\times 25^{4}}\) - step9: Multiply the fractions: \(\frac{429^{5}}{8192\times 25^{4}}\) The final amount after investing R3200 for 5 years at a compound interest rate of 7.25% per annum is approximately R4540.84. Rounding off to 2 decimal places, the final amount is R4540.84.

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The Deep Dive

To calculate the final amount using compound interest, you can use the formula: \[ A = P(1 + r/n)^{nt} \] Where: - \( A \) is the amount of money accumulated after n years, including interest. - \( P \) is the principal amount (the initial amount of money). - \( r \) is the annual interest rate (decimal). - \( n \) is the number of times that interest is compounded per year. - \( t \) is the time the money is invested for in years. In this case: - \( P = 3200 \) - \( r = 0.0725 \) - \( n = 1 \) (compounded annually) - \( t = 5 \) Plugging the values into the formula gives: \[ A = 3200(1 + 0.0725/1)^{1 \times 5} \] \[ A = 3200(1 + 0.0725)^{5} \] \[ A = 3200(1.0725)^{5} \] Calculating: \[ (1.0725)^{5} \approx 1.4192 \] Then: \[ A \approx 3200 \times 1.4192 \approx 4538.78 \] Therefore, the final amount after 5 years is approximately **R4538.78** when rounded to two decimal places.

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