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3.2 It takes 6 painters \( 41 / 2 \) hours to paint these classrooms 3.2.1 Calculate how long 3 painters will take to complete the same job. 3.2 .2 Is this direet or indirect proportion? 3.2.3 Givo a reason for your answer.

Ask by Gonzalez Gross. in South Africa
Feb 23,2025

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3.2.1 It takes 3 painters 9 hours to complete the job. 3.2.2 The relationship is indirect proportion. 3.2.3 As the number of painters increases, the time needed to finish the job decreases, which is an inverse proportion.

Solution

We start by noting that if 6 painters take 4½ hours to complete the job, then the total work can be expressed as:   Total work = Number of painters × Time = 6 painters × 4.5 hours = 27 painter‐hours. 3.2.1 For 3 painters, the time required (T) can be found by setting:   3 painters × T = 27 painter‐hours Solve for T:   T = 27 ÷ 3 = 9 hours So, 3 painters will take 9 hours to complete the same job. 3.2.2 The relationship between the number of painters and the time taken is an inverse (or indirect) proportion. 3.2.3 This is because as the number of painters increases, the time required to complete the work decreases proportionally, and vice versa. For example, if you double the number of painters, the time is halved, which is the characteristic behavior of an inverse proportional relationship.

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To calculate how long 3 painters will take to complete the same job, first, determine the total hours of work done by 6 painters in \(4.5\) hours, which is \(6 \times 4.5 = 27\) painter-hours. If 3 painters are working, the time taken to finish the job can be calculated by dividing the total painter-hours by the number of painters: \(27 \div 3 = 9\) hours. So, 3 painters will take \(9\) hours to complete the job. This is an indirect proportion. As the number of painters decreases, the time taken to complete the job increases. Inverse relationships like this indicate that when one quantity goes down, the other goes up, demonstrating that painter efficiency and time taken are related inversely. The example shows how work dynamics change based on the resource at hand!

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